Absolute value inequality solution |2X-1|-|X-2|<1 How to solve it with the number axis method,

Absolute value inequality solution |2X-1|-|X-2|<1 How to solve it with the number axis method,

First find the zero point.2x-1=0, x=1/2; x-2=0, x=2 The absolute value of this problem has two zero points, i.e. x=1/2 and x=2 can be divided into three areas on the number axis: x <1/2,1/2≤x <2, x≥2When x <1/2,[-(2x-1)]-[-(x-2)]<1,1-2x+x-2<1,解得1/2> x >-2; When 1/2≤x <2,2x-1+x-2...

How much is one-half plus two, one-square plus two, one-square plus two, one-square plus two, to the 2010 power of two How much is one-half plus two, one-square plus two, one-square plus two, one-square plus two, to the 2010 power of two?

12=1-1/2;1/2^2=1/2-1/2^2;1/2^3=1/2^2-1/2^3;.1/2^2010=1/2^2009-1/2^2010. The two ends of the above equations are respectively added to obtain:1/2+1/2^2+1/2^3+.+1/2^2010=1-1/2^2010.