(-2) To the 2007 power +(-2) to the 2008 power

=-(½)^2007+(½)^2008
=-(1/2)^2007+1/2*(1/2)^2007=-1/2*(1/2)^2007
=-1/2^2008

What is the one-to-five power of a for 2006 minus a for 2005? What is the power of a 2006 minus the power of a 2005?

A^2006-1/a^2005
=A^2006-a^(-2005)
= A^(-2005)*(a^4011-1)
=(A^4011-1)/a^2005

A^2006-1/a^2005
= A^2006-a^(-2005)
= A^(-2005)*(a^4011-1)
=(A^4011-1)/a^2005

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