If the squares of |a-1| and (b+2) are mutually opposite, find the value of (a+b) to the 2008th power +a2007th power. If the squares of |a-1| and (b+2) are mutually opposite, find the value of (a+b) to the 2008th power + a to the 2007th power.

If the squares of |a-1| and (b+2) are mutually opposite, find the value of (a+b) to the 2008th power +a2007th power. If the squares of |a-1| and (b+2) are mutually opposite, find the value of (a+b) to the 2008th power + a to the 2007th power.

If |a-1| and the square of (b+2) are mutually opposite
=>
Square of |a-1(b+2)=0
The absolute value and that square are non-negative,
Their sum is 0
Both must be 0
So a-1=0, b+2=0
A=1, b=-2
2008 Power of (a+b)+2007 power of a
=(1-2)2008 Power +1 2007 power
=1+1
=2

What is the square of 2-2 minus the third power of 2, the 2007 power of 2, and the 2008 power of 2

Original formula =2^2008-2^2007-2^2006.-2^2+2
=(2*2^2007-2^2007)-2^2006.-2^2+2
=2^2007-2^2006.-2^2+2
=(2*2^2006-2^2006)-.-2^2+2
=2^2006-.-2^2+2
.
=2^2+2
=4+2
=6