1.2008 Power of 2008 power of (-2) x ()2008 power 2.(minus five-eighth)2009 power x (eight-fifths)2010 power 3. 1.(-2)2008 Power x (minus one-half)2008 power 2.(minus five-eighth)2009 power x (eight-fifths)2010 power 3.

1.2008 Power of 2008 power of (-2) x ()2008 power 2.(minus five-eighth)2009 power x (eight-fifths)2010 power 3. 1.(-2)2008 Power x (minus one-half)2008 power 2.(minus five-eighth)2009 power x (eight-fifths)2010 power 3.

1.(1)
2.(Negative eight-fifths)
It should be what it should be. Just combine them.
(-2)*(Minus one-half) to the 2008 power
(Minus five-eighths)*(eight-fifths) to the power of 2009*(eight-fifths)

1.(1)
2.(Negative eight fifths)
That's what it should be. It's as simple as combining them.
(-2)*(Minus one-half) to the 2008 power
(Minus five-eighths)*(eight-fifths) to the power of 2009*(eight-fifths)

1.(1)
2.(Negative eight-fifths)
That's what it should be. Just combine them.
(-2)*(Minus one-half) to the 2008 power
(Minus five-eighths)*(eight-fifths) to the power of 2009*(eight-fifths)

Given that ab is mutually opposite, the absolute value of the reciprocal x of cd is equal to 2 and the square of x +(a+b+cd) x cd) x +(a + b) to the power of 2009+(-cd) of 2010 Given that ab is mutually opposite, the absolute value of the reciprocal x of cd is equal to 2, and the square of x +(a+b+cd) x+(a+b) to the power of 2009+(-cd) to the 2010

I.e. a+b=0, cd=1
X=±2
X2=4
So original formula =4+(0+1) x+0+1
=4+X+1
=5±2
=3 Or 7