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Given that a and b are mutually opposite numbers, c and d are mutually reciprocal numbers, the absolute value of x is equal to 3, try to find the power of x^2-(a+b+cd) x+(a+b)2009 Given that a and b are mutually opposite numbers, c and d are mutually reciprocal numbers, the absolute value of x is equal to 3, try to find the power of x^2-(a+b+cd) x+(a+b)2009+(-cd)2010
(X^2-x)^3-2010 under reduction
Then discuss the value of x.
When x=3, the above formula =6^3-2010=-1794
When x=-3, the above formula =12^3-2010=-282
(X^2-x)^3-2010
Then discuss the value of x.
When x=3, the above formula =6^3-2010=-1794
When x=-3, the above formula =12^3-2010=-282
The absolute value of a minus one plus the quadratic of (b+2) is equal to zero, so as to obtain the 2010 power of (a+b)+ the 2010 power of a
Because |a-1(b+2)^2=0
So a-1=0, b+2=0
So a=1, b=-2
So (a+b)^2010+a^2010=(-1)^2010+1^2010=1+1=2
RELATED INFORMATIONS
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