Given that the absolute value of a-b-1 is opposite to the second power of 3(a-2), find the value of ab. Please, teach me.

And the absolute value of a-b-1+2 power of 3(a-2)=0
So a-b-1=0
A-2=0
So a =2
B=a-1=1
So ab=2

Judge 2007 power of 2006 plus 2008 power of 2009

The estimate is to judge what the last digit is.
The end of any power in 2006 is 6
The odd power end of 2009 is 9 and the even power end of 2009 is 1
So mantissa =6+1=7

The estimate is to judge what the last digit is.
The end of any power in 2006 is 6
In 2009, the odd-numbered terminal mantissa is 9 and the even-numbered terminal mantissa is 1
So mantissa =6+1=7

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