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Vector a=(3, m), b=(-1,-4), and a, b are collinear, then the value of m is? At -4/3,-3/4 4/3 How about 3/4?
From the title,-m=-12, m=12
The subject is wrong, or you have copied it wrong
For vector a (x1, y1)//b (x2, y2) is equivalent to x1y2=x2y1.
M=12
Vector a=(3,12)=-3(-1,-4)=-3 vector b, you say collinear?
According to the meaning,-m=-12, m=12
The subject is wrong, or you have copied it wrong
For vector a (x1, y1)//b (x2, y2) is equivalent to x1y2=x2y1.
M=12
Vector a=(3,12)=-3(-1,-4)=-3 vector b, you say collinear?
A. The unit vectors are all equal B. Any vector is not equal to its opposite vector C. Parallel vectors are not necessarily collinear D. Vector with module 0 is collinear with any vector
The unit vector is 1, and the direction is not necessarily the same
The 0 vector is equal to his opposite vector
A vector with modulus 0 is parallel to any vector, but not collinear
So choose C
The unit vector is 1 and the direction is not necessarily the same
The 0 vector is equal to his opposite vector
A vector with modulus 0 is parallel to any vector, but not collinear
So choose C
Is it true that the unit vector of any non-zero vector a is a/|a|. (Note:→ above letters)
0
Given that a and b are a set of bases representing all vectors in a plane, what of the following four sets of vectors can not be used as a set of bases? (And explain why)... Given that a and b are a set of bases representing all vectors in a plane, what of the following four sets of vectors can not be used as a set of bases? (And explain why)(1) a and a+b (2) a-2b and b-2a (3) a-2b and 4b-2a (4) a+b and a-b
0
The bases of the following groups of vectors that represent all vectors in their planes are A.e1=(-1,2) e2=(5,7) B.e1=(3,5), e2=(6,10) C.e1=(4,-6), e2=(1/4,-3/8) To elaborate on why, I'm not very clear about the concept of the base. The bases of the following groups of vectors that can represent all vectors in their planes are A.e1=(-1,2) e2=(5,7) B.e1=(3,5), e2=(6,10) C.e1=(4,-6), e2=(1/4,-3/8) To elaborate on why, I don't know much about the concept of base... The bases of the following groups of vectors that can represent all vectors in their planes are A.e1=(-1,2) e2=(5,7) B.e1=(3,5), e2=(6,10) C.e1=(4,-6), e2=(1/4,-3/8) To elaborate on why, I'm not very clear about the concept of the base.
B.
.E1=1/2e2
Of the following vectors,() A. A =(0,0), B=(1,2) B. A =(5,7), B=(−1,2) C. A =(3,5), B=(6,10) D. A =(2,−3), B =(−1 2, 3 4)
0
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