In the triangle, how to prove the "five-center" point with a vector? I'm talking about how each of them can prove it. For example, how to prove that the vertical center is the intersection of three high lines, only one. How do we prove the "five-center" intersection in a triangle with a vector? I'm talking about how each of them can prove it. For example, how to prove that the vertical center is the intersection of three high lines, only one. In the triangle, how to prove the "five hearts" with a vector? I'm talking about how each of them can prove it. For example, how to prove that the vertical center is the intersection of three high lines, only one.

In the triangle, how to prove the "five-center" point with a vector? I'm talking about how each of them can prove it. For example, how to prove that the vertical center is the intersection of three high lines, only one. How do we prove the "five-center" intersection in a triangle with a vector? I'm talking about how each of them can prove it. For example, how to prove that the vertical center is the intersection of three high lines, only one. In the triangle, how to prove the "five hearts" with a vector? I'm talking about how each of them can prove it. For example, how to prove that the vertical center is the intersection of three high lines, only one.

For the triangle of the five-centered meaning, the heart, the heart, the heart and the heart, they should be five points! The center of gravity is the point of intersection of three high lines, only one. The center of gravity is the point of intersection of three angle bisectors, only one. The center of gravity is the point of intersection of three midlines, only one. The center of gravity is the point of intersection of three midlines, only one.

For the triangle of the five-centered meaning of the center of gravity, the heart, the heart, the heart and the heart, they should be five points! The center of gravity is the point of intersection of three high lines, only one. The center of gravity is the point of intersection of three angle bisectors, only one. The center of gravity is the point of intersection of three midlines, only one. The center of gravity is the point of intersection of three midlines, only one.

Vector Representation of Triangular Four Centers

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How the inner is represented in the vector

Given that O is the inner part of the triangle ABC, a, b, c are the length of the opposite sides of A. B. C. Then aOA+bOB+cOC=0(OA, OB, OC all directives). It is proved that if the triangle ABC, AD is the angle bisector of BC, the inner part is O.|BC|=a,|AC|=b,|AB|=caOA+bOB+cOC=aOA+b (AB+OA)+c (AC+OA)=(a+b+c) OA+b (DB-...

The problem of combining the inner triangle with the vector. Let I be the inner value of the triangle ABC, AB=AC=5, BC=6, vector AI=m (multiple) vector AB+n (multiple) vector BC, the sum value. Let I be the inner of the triangle ABC, AB=AC=5, BC=6, vector AI=m (multiple) vector AB+n (multiple) vector BC, and find the value of M and N. The problem of combining inner triangle with vector. Let I be the inner value of the triangle ABC, AB=AC=5, BC=6, vector AI=m (multiple) vector AB+n (multiple) vector BC, and sum the values. Let I be the inner of the triangle ABC, AB=AC=5, BC=6, vector AI=m (multiple) vector AB+n (multiple) vector BC, find the value of M and N. The problem of combining inner triangle with vector. Let I be the inner value of the triangle ABC, AB=AC=5, BC=6, vector AI=m (multiple) vector AB+n (multiple) vector BC, the sum value. Let I be the inner of the triangle ABC, AB=AC=5, BC=6, vector AI=m (multiple) vector AB+n (multiple) vector BC, find the value of M and N.

DI is parallel to BC through point I, and intersects AB at point D. Connect AI and extend BC to E'm vector AB+n vector BC', i.e.'vector AD+vector DI'. Because DI is parallel to BC, AD is parallel to AB, so M*vector AB=vector AD N*vector BC=vector DI It is easy to know the radius of tangent circle of triangle 1.5, so EI=1.5 is known by similarity AD=25/...

Please use the vector method to prove that the three center lines of any triangle are coincident. Please use the vector method to prove that any triangle three - line point.

Let the triangle be ABC and the three center lines be AD, BE and CF, then the vector AD=1/2*(vector AC+vector AB), the vector BE=1/2*(vector BA+vector BC), the vector CF=1/2*(vector CA+vector CB).

Given the vector a=(sinx,3/2), b=(cosx,-1). When a is parallel to b, find the square of 2cosx-sin2x

Sinx*(-1)=3/2*cosx
Sinx/cosx=-3/2
Tanx=-3/2
2(Cosx)^2-sin 2x
= Cos2x+1-sin2x
=[1-(Tanx)^2]/[1+(tanx)^2]-2(tanx)/[1+(tanx)^2]+1
=[1-(Tanx)^2-2(tanx)]/[1+(tanx)^2]+1
=[1-9/4+3]/[1+9/4]+1
=16/13