Given that the module of a vector is equal to 1, the module of b vector is equal to 2, find (a vector+2b vector)(2a vector-b vector)

Given that the module of a vector is equal to 1, the module of b vector is equal to 2, find (a vector+2b vector)(2a vector-b vector)

Dismantle the vector form into 2a square-ab+4ab-2ab, and then quantity product to make

Disassemble the vector form into 2a square-ab+4ab-2ab, and then use the quantity product to

If the angle between vector a and vector b is 25, then why is the angle between vector 2a and vector -3/2b 155°?

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If the angle between vector a and b is 25, then why is the angle between vector 2a and -3/2b 155°? Answer with the knowledge of Grade One and Grade Four If the angle between vectors a and b is 25, then why is the angle between vector 2a and -3/2b 155°? Answer with the knowledge of Grade One and Grade Four

You may not know the concept, this question is very easy to answer. First, the vector is a direction and size of the line, it has the initial position and the final position. The positive and negative of the vector represents its direction of the "positive and negative "(e.g. left, right, up and down). And 2a is the number of vectors, that is, the direction of the line is lengthened or shortened several times, without affecting the square.

You may not know the concept, this question is very easy to answer. First, the vector is a direction and size of the line, it has the initial position and the final position. The positive and negative of the vector represents its direction of the "positive and negative "(for example, left, right, up and down). And 2a is the number of vectors, that is, the direction of the line is lengthened or shortened several times, without affecting the square.

Given plane vector A =(1,1), B=(1,-1), then vector 1 2 A-3 2 B=______. Given plane vector A =(1,1), B=(1,-1), then vector 1 2 A-3 2 B =______.

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Given plane vector A =(1,1), B=(1,−1), then vector 1 2 A−3 2 B =() A.(-2,-1) B.(-1,2) C.(-1,0) D.(-2,1)

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Given the plane vector a, b,|a|=1,|b|=2, a⊥(a-2b), then the value of |2a+b|

From a⊥(a-2b),
A*(a-2b)=a^2-2a*b=1-2a*b=0,
A*b=1/2.
(2A+b)^2=4a^2+4a*b+b^2=4+2+4=10,
|2A+b|=√10.