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Given vector a=(6,4), vector b=(3,8), and x multiplied by vector a+y multiplied by vector b=(-3,5), then x equals y equals Is it done with vector addition?
X (6,4)+y (3,8)=(-3,5)
6X+3y=-3
4X+8y=5
Y =7/6
In triangle ABC, if AB vector point is multiplied by AC vector = AB vector point is multiplied by CB vector =4, then the length of AB is
0
In triangle ABC, if D is a point on the edge of AB, if vector AD=2DB, vector CD=1/3CA CB, then λ is equal to?
Vector AB=CB-CA,
Vector AD=2DB,
Then vector AD=2/3AB=2/3(CB-CA)=2/3CB-2/3CA,
Vector CD=CA+AD=1/3CA+2/3CB,
I.e.λ=2/3.
In triangle ABC, where D is a point on the edge of AB, if vector AD=2 vector DB, vector CD=1/3 vector CA+x vector CB, then x equals A.2/3 B.1/3 C.-1/3 D.-2/3 In a triangle ABC, where D is a point on the edge of AB, if vector AD=2 vector DB, vector CD=1/3 vector CA+x vector CB, then x equals A.2/3 B.1/3 C.-1/3 D.-2/3
According to the fundamental theorem of plane vector, any two non-collinear vectors in a plane can be used as bases, and any vector can be represented by a base vector and the expression is unique. Because vector AD=2 vector DB, vector CD-vector CA=2(vector CB-vector CD), vector CD=vector CA+2 vector CB, vector CD...
According to the fundamental theorem of plane vector, any two non-collinear vectors in a plane can be used as bases, and any one of them can be represented by a base vector expression is unique.
If the vector AB is multiplied by the vector BC minus the square of AB equals 0, what triangle is the triangle ABC? Answer obtuse triangle
AB×BC-AB×AB=0
AB×(BC-AB)=0
If a triangle exists, AB is not equal to 0.
So BC-AB=0, i.e. BC=AB
Triangular isosceles triangle
In triangle ABC, the side length of inner angle A, B, C is a.b.c, vector AB is multiplied by vector AC equal to 8, angle BAC equal to θ, a equal to 4, and b is multiplied by the maximum value of c and the value of θ. Is the value range of θ
Vector AB multiplied by vector AC equals 8
I.e. bc×cosθ=8 1
Another cosine theorem.
Cos θ=(b2+c2-a2)/2bc2
From 1 2
B2+ c2- a2=16
And a=4
Then b2+ c2=32
Thus bc≤[ b2+ c2]/2=32/2=16
Equals get at b=c=4
The triangle ABC is an equilateral triangle
So θ=60°
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