If an isosceles triangle has a right angle and its area is 50 square centimeters, then the sum of its two right angles is______ Centimeter

If an isosceles triangle has a right angle and its area is 50 square centimeters, then the sum of its two right angles is______ Centimeter

Because 50 × 2 = right angle side × right angle side,
So the right angle side is 10 centimeters,
2 × 10 = 20 (CM);
A: the sum of the two right angles is 20 cm
So the answer is: 20

The sum of two right angle sides of a right triangle is 14 cm and the area is 24 cm 2

If one of the right angles is xcm, the other is (14-x) cm long,
One
2×x(14-x)=24,
It is found that X1 = 6, X2 = 8,
When X1 = 6, 14-x = 8;
When x2 = 8, 14-x = 6;
A: the lengths of the two right angles are 6 and 8

The right angle side of an isosceles triangle is one fifth of a decimeter long and its area is () square centimeter?

1 / 5 decimeter = 2 cm
The area is 2 * 2 * 1 / 2 = 2 square centimeters

The three sides of a right triangle are 6cm, 8cm and 10cm respectively. The area of this triangle is () square centimeter

The three sides of a right triangle are 6cm, 8cm and 10cm respectively
6²+8²=36+64=100=10²
So, according to the Pythagorean theorem, 6cm and 8cm are two right angle sides
The area of this triangle is 1 / 2 × 6 × 8 = 24 square centimeter

One side of an isosceles right triangle is 8 cm. What is the largest square centimeter and the smallest square centimeter

Let a triangle have a right angle side, then the base edge is a radical 2
Therefore, the area is the smallest when the bottom side length is 8, and the area is the largest when the right angle side length is 8
Maximum area = 8 * 8 / 2 = 32 square centimeter
Minimum area = (8 / root 2 * / root 2) / 2 = 16 square centimeter

9. An isosceles right triangle has a side of 8 cm. Its maximum area is () square centimeter and its minimum is () square centimeter 9. An isosceles right triangle has a side of 8 cm. Its maximum area is () square centimeter and its minimum is () square centimeter

8 × 8 △ 2 Minimum: 8 △ 2 = 4 (CM)
=64÷2 4×8÷2
=32(cm²) =32÷2
=16(cm²)

An isosceles right triangle has a right angle side of 8 cm long and its area is______ Square centimeter

8×8÷2
=64÷2
=32 (square centimeter)
A: its area is 32 square centimeters;
So the answer is: 32

The sum of two right angle sides of a right triangle is 14 cm and the area is 24 cm 2

If one of the right angles is xcm, the other is (14-x) cm long,
One
2×x(14-x)=24,
It is found that X1 = 6, X2 = 8,
When X1 = 6, 14-x = 8;
When x2 = 8, 14-x = 6;
A: the lengths of the two right angles are 6 and 8

Given that the sum of the two right angles of a right triangle is 14 and the length of the hypotenuse is 10, find the area of the triangle

If one right angle side length is x, the other right angle side length is 14-x
X^2+(14-X)^2=10^2
X^2+196-28X+X^2=100
X^2-14X+48=0
(X-6)(X-8)=0
X = 6 or x = 8
When x = 6, the other side = 14-6 = 8
When x = 8, the other side = 14-8 = 6
The area of this triangle
=8*6/2
=24

The sum of two right angle sides of a right triangle is 14 cm and the area is 24 cm 2

If one of the right angles is xcm, the other is (14-x) cm long,
One
2×x(14-x)=24,
It is found that X1 = 6, X2 = 8,
When X1 = 6, 14-x = 8;
When x2 = 8, 14-x = 6;
A: the lengths of the two right angles are 6 and 8