In ABC + S 2, we find the maximum area of △ 2, C = 2 for the root of ABC

In ABC + S 2, we find the maximum area of △ 2, C = 2 for the root of ABC

4{sin[(A+B)/2]}^2-cos2C=7/2,
2[1-cos(A+B)]-cos2C=7/2,
2+2cosC-2(cosC)^2+1=7/2,
2(cosC)^2-2cosC+1/2=0,
cosC=1/2,C=60°,
5 c=√7,c=√7/5,
By the sine theorem, a = csina / sinc, B = csinb / sinc,
The area of △ ABC = (1 / 2) absinc = (C ^ 2 / 2) sinasinb / sinc = [7 / (25 √ 3)] sinasinb
=[7/(50√3)][cos(A-B)-cos(A+B)]=[7/(50√3)][cos(A-B)+1/2],
The maximum value obtained is 7 √ 3 / 100

The ratio of the three inner angles of a triangle is 3:3:4, which is a () triangle by its sides and a () triangle by its angles An isosceles triangle is divided by its sides, and an isosceles triangle is divided according to its angle,

Ratio of internal angle = 3:3:4
Then the internal angles are 180 * 3 / 10 = 54 °, 54 ° and 72 ° respectively
It is an isosceles triangle
It is a triangle with acute angle

The ratio of the three inner angle degrees of a triangle is l: 3:5. The largest angle of this triangle is () degree, which is classified as () triangle by angle

100 obtuse angle

If the ratio of the degrees of the three inner angles of a triangle is a: 1:2, when a = (), the triangle is a right triangle, When a = (), the triangle is an isosceles triangle. The ratio of radius to circumference of a circle is (), and π is reserved

If the degree ratio of the three inner angles of a triangle is a: 1:2, when a = (6), the triangle is a right triangle, when a = (1 or 2), the triangle is isosceles triangle,
The ratio of radius to circumference of a circle is (1 / 2 π), and π is retained

The sum of the two outer angles of a triangle is 270 degrees, and the difference of its inner angles is 30 degrees. Find the degrees of the three inner angles of the triangle

If the difference between the inner angles of the two outer angles is 30 °, the difference between them is also 30 °,
So they are (270 ° + 30 °) / 2 = 150 ° and (270 ° - 30 °) / 2 = 120 ° respectively
So their internal angles are 30 ° and 60 ° respectively,
Another internal angle: 90 degrees

The sum of the two outer angles of a triangle is 270 degrees, and the difference between their two internal angles is 30 degrees. Find the degrees of the three inner angles of the triangle

Two outer angles and 270, so two inner angles and 90
The other angle is 90, and the difference between the two internal angles is 30
x+y=90
x-y=30
x=60 y=30
So the three corners are 30, 60, 90

The ratio of degrees of the three exterior angles of △ ABC is 2:3:4, and the smallest inner angle of the triangle is equal to______ °．

2k and 3k, respectively,
From the meaning of the title, 2K + 3K + 4K = 360 °,
K = 40 ° is obtained,
The three external angles are 80 degrees, 120 degrees and 160 degrees respectively,
The minimum internal angle of △ ABC is 180 ° - 160 ° = 20 °
So the answer is: 20

The degree ratio of the three inner angles of a triangle is 1:6:5, and the largest inner angle is______ Degrees, in terms of angles, it's a______ Angle triangle

180°×6
1+6+5，
=180°×1
2，
=90°；
Because one of them is 90 degrees, this triangle is a right triangle
So the answer is: 90, straight

The ratio of the three inner angles of a triangle is 1:1:2 In terms of angle, is this triangle () triangle?

The maximum angle of this triangle is 180 * 2 / (1 + 1 + 2) = 90 degrees
In terms of angles, this triangle is a (right angle) triangle

The ratio of the three inner angle degrees of a triangle is 1:1:2. What is its maximum angle? This triangle is ()

Glad to answer your question ~!
This is an isosceles right triangle with a maximum angle of 90 ° and the other two angles are 45 degrees
In this problem, we can make an equation, and let the degree of the minimum angle be X
Then x + X + 2x = 180 ° and thus x = 45 ° so the maximum angle is equal to 45 ° x 2 = 90 °