In the triangle ABC, the angle a plus the angle B is equal to the angle c, and the angle B is equal to twice the angle A. find the degree of the angle a, the angle B and the angle C

In the triangle ABC, the angle a plus the angle B is equal to the angle c, and the angle B is equal to twice the angle A. find the degree of the angle a, the angle B and the angle C

a=30,b=60,c=90

In triangle ABC, angle a minus angle B is equal to 15 degrees and angle c is equal to 75 degrees

The sum of the inner angles of the triangle is 180 degrees, the angle c is equal to 75 degrees, and the sum of that angle a plus angle B is 105 degrees. Because angle a minus angle B equals 15 degrees, angle a = 60 degrees and angle B = 45 degrees

As shown in the figure, △ ABC ≌ △ ade, and ∠ CAD = 10 °, B = ∠ d = 25 °, EAB = 120 °, calculate the degrees of ∠ DFB and ∠ DGB

∵△ABC≌△ADE,
∴∠DAE=∠BAC=1
2(∠EAB-∠CAD)=1
2(120°−10°)=55°.
∴∠DFB=∠FAB+∠B=∠FAC+∠CAB+∠B=10°+55°+25°=90°
∠DGB=∠DFB-∠D=90°-25°=65°.
To sum up, ∠ DFB = 90 °, DGB = 65 °

Triangle ABC is equal to triangle ade and angle CAD is equal to 10 degrees, angle B is equal to angle D is equal to 25 degrees, and ead is equal to 125 degrees. The degrees of angle DFB and angle DGB are calculated

Where's your FG from? Just mark it for you!

As shown in the figure, △ ABC ≌ △ ade, and ∠ CAD = 10 °, B = ∠ d = 25 °, EAB = 120 °, calculate the degrees of ∠ DFB and ∠ DGB

∵△ABC≌△ADE,
∴∠DAE=∠BAC=1
2(∠EAB-∠CAD)=1
2(120°−10°)=55°.
∴∠DFB=∠FAB+∠B=∠FAC+∠CAB+∠B=10°+55°+25°=90°
∠DGB=∠DFB-∠D=90°-25°=65°.
To sum up, ∠ DFB = 90 °, DGB = 65 °

In this paper, the relation between the upper corner of the graph and the upper corner of the graph is determined

∵①∠dac﹢∠c=∠ade﹢∠edb,②∠aed=∠b﹢∠edb,③∠b=∠c
ν ① - ②: 2 ∠ EDB = ∠ DAC

As shown in the figure, along the triangle ABC and the triangle ade are congruent triangles. The extension line angle of BC AD and point F, angle de at point G, angle ACB = 105 degrees, angle CAD = 10 degrees, angle d = 25 degrees, calculate the degrees of angle EAC, angle DFB and angle DGB

Because the triangle ABC and the triangle ade are congruent, angle B = angle D angle DAE = angle BAC because angle ACB = 105 degrees angle d = 25 degrees angle B = 25 degrees because angle ACB + angle B + angle BAC = 180 degrees, angle BAC = 50 degrees, so angle DAE = 50 degrees because angle EAC = angle CAD + angle DAE angle CAD = 10 degrees, angle EAC = 50 + 10 = 60 degrees because angle DFB =

In triangle ABC, if angle C plus angle a equals two angles B and angle c minus angle a equals 80 degrees, then what degree is angle c angle B angle a

Let the angles a, B and C be a, B and C respectively
c+a=180-b=2b
b=60
c-a=80
c=100 a=20

In the triangle ABC, angle a + angle B = 100 ° angle c = 2 angle B, calculate the degree of angle a, angle B and angle C

Angle a = 100 degrees - angle B
Angle a + angle + angle c = 180 degrees
100 degrees - angle B + angle B + 2 angle B = 180 degrees
Angle B = 40 degrees,
Angle a = 60 degrees,
Angle c = 80 degrees

In △ ABC, ∠ a - ∠ B = 36 °, C = 2 ∠ B, calculate the degree of ∠ B

∵∠A-∠B=36°,
∴∠A=∠B+36°,
According to the theorem of the sum of interior angles of triangles, it is found that ∠ a + ∠ B + ∠ C = 180 °,
∴∠B+36°+∠B+2∠B=180°,
The solution is ∠ B = 36 °