A two digit number is 5 times the sum of its two Arabic numerals, which is 10 times larger than the two digit number （□+□）×5-10=□

Let the two Arabic numerals of this two digit number be a and B,
So (a + 5) × 5 - (10a + b) = 1,
5a+25-10a-b=10
5a+b=15，
So a = 1, B = 10
A = 2, B = 5
So the two digit number is 25
A: the two digit number is 25

A two digit number. Five times the sum of the Arabic numbers is 10 times more than this number

The two digits: 10A + B,
5(a+b)=10a+b+10
5a=4b-10
a=2,b=5
The two digits: 25

The first power of 3 = 3, the second power of 3 = 9, the third power of 3 = 27,,,,,,, according to this rule, then the number of digits of the 2009 power of 3 is () To be clear,

Find the rules first
Mantissa: three times three is three, two three three is nine, three three three is seven, four three three is one
Five three-phase multiplication is three, six three-phase multiplication is nine, seven three-phase multiplication is seven, eight three-phase multiplication is one
.
It can be found that their mantissa is 39 7 1, and these four numbers are in circulation
Therefore, we use 2009 △ 4 = 502 to make up 1
This shows that these four numbers have been cycled 502 times, there is still a number left, and then count again from the beginning, that is 3, so the digit number of the 2009 power of 3 is 3

Look at the following numbers: the first power of 3 is equal to the second power of 3, and the third power of 9 3 is equal to 27, the fourth power of 3 is 81, and the fifth power of 3 is 243

3 ^ 1 = 3, bits are 3
3 ^ 2 = 9, bits are 9
3 ^ 3 = 27, bits are 7
3 ^ 4 = 81, bits are 1
3 ^ 5 = 243, bits are 3
3 ^ 6 = 729, bits are 9
The fifth power and the first power have the same bit
The 6th power and 2nd power have the same bit
……
So it's four in a loop
2008=4*501+4
So 3 ^ 2008 bits are the same as 3 ^ 4 bits
So 3 ^ 2008 bits are 1

What is the digit number of the 8th power of 1 + the 8th power of 2 + the 8th power of 3 + the 8th power of 4 + the 8th power of 5 + the 8th power of 6 + the 8th power of 7 + the 8th power of 8 + the 8th power of 9

The digit numbers of the 8th power of 1, the 8th power of 2, the 8th power of 3, the 8th power of 4, the 8th power of 5, the 8th power of 6, the 8th power of 7, the 8th power of 7, the 8th power of 8, and the 8th power of 9 are respectively 1,6,1,6,6,5,6,1,6,1, so the 8th power of 1 + the 8th power of 2 + the 8th power of 3 + the 8th power of 4 + the 8th power of 5 + the 8th power of 6 + the 8th power of 7 + 8

What is the digit number of the 20th power of 7 * 8 to the 2010th power * 9 to the 2014 power

The 20 th power mantissa of 7 is 1, the 201 th power mantissa of 8, the 2014 mantissa of 9 is 1, and the final number of digits multiplied is 8
The nth power mantissa of 7 is 7,9,3,1. Circulation tube, 20 divided by 4 is exactly 5, and the remainder is zero, so the mantissa is 1

The first power of 3 = 3, the second power of 3 = 9, the third power of 3 = 27, the fourth power of 3 = 81, the fifth power of 3 = 243. Write the last digit of the 2013 power of 3

The last number of 3 ^ n is about the 3,9,7,1 loop
2013/4=503.1
So the number at the end of 3 ^ 2013 is: 3

Who created the Arabic numerals

Arabic numerals were invented by Indians, passed from Arabs to Europe and modernized by Europeans
In the 3rd century AD, an Indian scientist, Bagdad, invented the Arabic numerals

Who created the Arabic numerals?

A: created by the Chinese
At that time, most of the Arabs were merchants. All of China's four great inventions were introduced into Western Europe by Arab merchants in business (along the Silk Road). The same is true of Chinese figures,

Why Arabic numerals

The internationally used number (invented by Indians, transmitted from Arabs to Europe, modernized by Europeans), is a total of 10 counting symbols: 0,1,2,3,4,5,6,7,8,9
Because Arabs spread to Europe, they are called Arabic numerals

A two digit number is 5 times the sum of its two Arabic numerals, which is 10 times larger than the two digit number （□+□）×5-10=□