The fast and slow trains run opposite each other. The fast train is 50 meters long and the slow train is 80 meters long. The speed of the fast train is twice that of the slow train. If the time for people sitting on the slow train to see the fast train passing through the window is 5 seconds, then the time for people sitting on the fast train to see the slow train passing through the window is 5 seconds______ Seconds

The fast and slow trains run opposite each other. The fast train is 50 meters long and the slow train is 80 meters long. The speed of the fast train is twice that of the slow train. If the time for people sitting on the slow train to see the fast train passing through the window is 5 seconds, then the time for people sitting on the fast train to see the slow train passing through the window is 5 seconds______ Seconds

80÷（50÷5），
=80÷10，
=8 (seconds);
A: the time for people on the express train to see the slow train passing through the window is 8 seconds
So the answer is: 8

The length of the fast and slow trains is 200 meters and 300 meters respectively. They run opposite each other. The time for people sitting on the slow train to see the fast train pass through this person's window is 8 seconds, while the time for people sitting on the fast train to see the slow train pass through this person's window is______ Seconds

300÷（200÷8）
=300÷25，
=12 (seconds);
A: it takes 12 seconds for people on the express train to see the slow train passing through this person's window
So the answer is: 12

The two fast and slow trains are 150 meters long and 200 meters long respectively, running on parallel tracks opposite each other. If the time for people sitting on the slow train to see the fast train passing through the window is 6 seconds, then the time for people sitting on the fast train to see the slow train passing through the window is______ Seconds

Let the time for people on the express train to see the slow train passing through the window be x seconds
one hundred and fifty
6=200
x，
The solution is x = 8,
It is proved that x = 8 is the solution of the original fractional equation
So the answer is 8

The fast and slow trains with body length of 150m and 250m respectively run on parallel tracks in the same direction. If the speed of the fast train is 80km / h, it will catch up with the super slow and slow down

Using the equation, the speed of idle train can be set as X km / h, 150 + 250 = 400 m = 0.4 km
Then 80 * 6 / 60 = 0.4 + X * 6 / 60
The solution is x = 76
answer
Arithmetic: 80-0.4 divided by (6 / 60) = 76

There are two trains. The fast train is 140 meters long and the slow train is 100 meters long. If the two trains go in the same direction, the fast train takes one minute from catching up with the slow train to leaving the slow train If the two cars run in opposite directions, the fast train shares 6S from meeting the slow train to leaving the slow train. Find the speed of the two cars Using binary quadratic equation

Set fast train speed x
Idle speed y
One minute = 60 seconds
The distance between the fast train catching up with the slow train and leaving the slow train is 140 + 100 = 240
（x-y）*60=240
The two trains run towards each other. The express train shares 6S from meeting the slow train to leaving the slow train,
（x+y）*6=240
namely
x-y=4
x+y=40
2x=44
X = 22 m / S
Y = 18 m / S

There are two fast and slow trains with a body of 150 meters and 250 meters respectively. The two trains run opposite each other on parallel tracks. If the speed of the fast train is 150 meters per hour, they There are two fast and slow trains with bodies of 150 meters and 250 meters respectively. The two trains are running on parallel tracks. If the speed of the fast train is 150 kilometers per hour, it takes 6 seconds from the front of the two trains to the rear of the two trains. (referred to as the passing period for short). Excuse me: (1) How many kilometers did the two cars travel during the passing period? (2) What is the speed of the local train?

(1) You draw a picture. The two cars have traveled a total of 250 + 150 = 400m
（2）（V1+V2）*6=400
V1+V2=150/3.6+V2=400/3
V2 = 25m / S = 90km / h