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The speed of a passenger car is 60 km / h and the speed of a freight car is 45 km / h. The freight car is 135 meters longer than the passenger car. If the two cars run opposite on the parallel track and the time they spend in the process of meeting is 30 seconds, the lengths of the passenger car and the freight car are ___
① Total length of two vehicles: (60 + 45) ÷ 60 × 0.5 = 0.875 (km) = 875 (m);
② Truck length: (875 + 135) ÷ 2 = 505 (m);
③ Coach length: 505-135 = 370 (m);
A: the passenger car is 370 meters long and the freight car is 505 meters long
So the answer is: 370 meters, 505 meters
A passenger car and a freight car run in the same direction on the parallel track. The passenger car is 220 meters long and the freight car is 320 meters long. The sum of the speed of the passenger car and the freight car is 32 meters per second. Now the passenger car catches up with the freight car from behind. If the time for the two cars to cross is 1 minute, calculate the speed of the two cars
If the time for two vehicles to cross is 1 minute, that is to say, the bus runs 220 + 320 = 540 meters more than the truck in 1 minute
Therefore, the speed of passenger cars is 9 meters per second faster than that of freight cars
Because the speed sum of passenger cars and trucks is 32 meters per second
Therefore, the bus speed is 20.5 meters per second and the truck speed is 11.5 meters per second
A passenger car and a freight car run on parallel tracks. The passenger car is 200 meters long and the freight car is 280 meters long Connect: The speed ratio of the passenger car to the freight car is 5:3. When the two cars travel in the same direction, the crossing time for the passenger car to catch up with the freight car is 1 minute. Find out the speed of the passenger car and the freight car Ideas and processes to solve problems
During the crossing time when the passenger car catches up with the freight car, the two cars should be displaced by a length of 200 + 280 = 480m
2. The relative displacement of the two vehicles is 480m, which takes 1 minute; Therefore, the relative speed difference is 480m / 60s = 8m / s
3. Assuming that the passenger car speed is 5x, the freight car speed is 3x; Then: 5x-3x = 8m / S; X=4m/s.
4 therefore, the bus speed is 20m / S; The truck speed is 12m / s
The speed of a passenger car is 90km / h, the speed of a freight car is 60km / h, and the freight car is 140m longer than the passenger car. If the two cars run in the same direction on the parallel track, the passenger The speed of a passenger car is 90km / h, the speed of a freight car is 60km / h, and the freight car is 140m longer than the passenger car. If the two cars travel in the same direction on the parallel track, and the passenger car catches up with the freight car from behind, the time for them to cross is 1min. Calculate the length of the passenger car. If the two cars travel opposite on the parallel track, what is the time for them to cross? Solving the first order equation with one variable
Set the length of the passenger car as x m;
If the two vehicles travel in the same direction on parallel tracks, it takes 1 minute for the bus to catch up with the truck from the back,
Within one minute, the passenger car traveled x + 140 meters more than the truck,
90 / 60 km for passenger cars in one minute = 1500 meters, 60 / 60 km for freight cars in one minute = 1000 meters,
Countable equation: x + 140 = 1500-1000,
The solution is: x = 360,
That is, the length of the bus is 360 meters;
Let the crossing time of driving in opposite directions be y hours,
In this y hour, buses and trucks have traveled a total of 140 + 360 meters = 0.5 kilometers,
Countable equation: 90Y + 60y = 0.5,
The solution is: y = 1 / 300,
That is, if the two vehicles run opposite on parallel tracks, their crossing time is 1 / 300 hour = 0.2 minutes = 12 seconds
A passenger car and a freight car run on a parallel track. The passenger car is 200 meters long and the freight car is 280 meters long. The speed ratio of the passenger car to the freight car is 5:3. The intersection time for the passenger car to catch up with the passenger car is 1 minute. What are the speeds of the passenger car and the freight car? A passenger car and a freight car run on a parallel track. The passenger car is 200 meters long and the freight car is 280 meters long. The speed ratio of the passenger car to the freight car is 5:3. The intersection time for the passenger car to catch up with the passenger car is 1 minute. What are the speeds of the passenger car and the freight car?
Catching up and Surpassing in one minute means that the bus runs 200 + 280 = 480 meters more than the train in one minute,
Speed difference:
V0 = 480 M / min
Because the ratio of train speed to bus speed is 3:5
Therefore, the speed of the bus:
V1=V0 × 5 / (5-3) = 1200 m / min
Truck speed:
V2=V1 × 3 / 5 = 720 M / min
Each of the two trains of Party A and Party B is 180m long. If the two trains run opposite to each other, it takes a total of 12s from the front to the rear. If the two trains run in the same direction, it will start from the train of Party A It takes 60s to meet the rear of B until the parking space of a exceeds the front of B. calculate the speed of B and B
Suppose the speed of car a is V1 and the speed of car B is V2, then 12 (V1 + V2) = 360 and 60 (V1 V2) = 360, and the solution is V1 = 18 and V2 = 12
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