The two trains come from opposite places of Party A and Party B. passenger cars travel 60 kilometers per hour and freight cars travel 55 kilometers per hour. When two cars meet, passenger cars travel more than freight cars 20 kilometers. What is the distance between Party A and Party B?

The two trains come from opposite places of Party A and Party B. passenger cars travel 60 kilometers per hour and freight cars travel 55 kilometers per hour. When two cars meet, passenger cars travel more than freight cars 20 kilometers. What is the distance between Party A and Party B?

Encounter time = 20 ÷ (60-55) = 4 hours
Distance = 4 × (60 + 55) = 460 km

The two trains are coming head-on from a and B. the passenger train is 60 km / h and the freight train is 55 km / h. The two trains meet The two trains are coming head-on from a and B. the passenger train is 60 km / h and the freight train is 55 km / h. When the two trains meet, the passenger train is 30 km longer than the freight train. How many kilometers are there between a and B?

You can do it without equations
According to the meaning of the topic, the passenger car travels 60-55 = 5km more than the truck per hour
At the time of meeting, the bus travels 30 kilometers more than the truck, so it takes 30 ÷ 5 = 6 hours for the two cars to meet,
Therefore, the distance between a and B is 6 × (60 + 55) = 690 km

A 120 meter long truck met an oncoming 160 meter long bus. It took 8 seconds from the front to the rear. The truck drove 17 meters per second, with no passengers How many meters does the car travel per second?

18 meters

It takes 80 seconds for a train to pass the 200 meter bridge and 72 seconds to pass the 114 meter long bridge No equations, just equations

Train speed: (200-114) ÷ (80-72) = 10.75 M / S
Conductor: 80 × 10.75-200 = 660m

A train passes through a 900 meter long railway bridge. It takes 1 minute and 25 seconds from the front of the train to the rear of the train. Then the train passes through a 1800 meter long tunnel. It takes 2 minutes and 40 seconds from the front of the train into the tunnel to the rear of the train to leave the tunnel. Calculate the speed of the train and the length of the body

1 minute 25 seconds = 85 seconds, 2 minutes 40 seconds = 160 seconds,
The train speed is: (1800-900) ÷ (160-85),
=900÷75,
=12 (M / s);
Body length: 85 × 12-900,
=1020-900,
=120 (m);
A: the speed of the train is 12 m / s and the length of the body is 120 M

A train passes through a 900 meter long railway bridge. It takes 1 minute and 25 seconds from the front of the train to the rear of the train. Then the train passes through a 1800 meter long tunnel. It takes 2 minutes and 40 seconds from the front of the train into the tunnel to the rear of the train to leave the tunnel. Calculate the speed of the train and the length of the body

1 minute 25 seconds = 85 seconds, 2 minutes 40 seconds = 160 seconds,
The train speed is: (1800-900) ÷ (160-85),
=900÷75,
=12 (M / s);
Body length: 85 × 12-900,
=1020-900,
=120 (m);
A: the speed of the train is 12 m / s and the length of the body is 120 M