Right triangle area formula

Right triangle area formula

S=ab/2
Where AB is the side length of two right angles!

How to calculate the area of a right triangle and what is the formula?  

Bottom multiplied by height divided by 2

Area formula of right triangle If the three sides of a right triangle are 10cm, 8cm and 6cm respectively, then the area of the right triangle is () square centimeters

“liu630799935”:
The area of a right triangle is the product of two right sides and divided by two
8 cm × 6cm ÷ 2 = 24cm2
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If we suddenly increase the centripetal force of an object in uniform circular motion, what will change That is, the centripetal force determines what size If we don't know whether it moves in a circular motion at a uniform speed after increasing the centripetal force, what is the impact of increasing the centripetal force?

To see what the size of the centripetal force determines, we need to see its definition formula F = (mv_2) / R. V is the linear velocity and R is the radius. In general motion with a velocity less than the speed of light, the mass will not change, so the centripetal force will only affect the linear velocity and motion radius and determine their size. Therefore, in the subject, in uniform motion, increase the centripetal force, that is, V remains unchanged, f becomes larger, and the radius will inevitably decrease

The centripetal force on an object moving in a uniform circular motion must be the same as () A is directly proportional to the square of linear velocity B is inversely proportional to the square of angular velocity C is inversely proportional to the radius of motion D is directly proportional to the product of linear velocity and angular velocity

F centripetal force = MV ^ 2 / r = MW ^ 2R = m (2 Pai / T) r = mvw
W is the angular velocity
According to the formula, you can know
A. D correct
B should be proportional
C should mean that when the speed is constant, it is inversely proportional

Try to find the centripetal force of a object moving in a uniform circular motion 7. As shown in the figure, the mass of both objects a and B is kg, Object a moves in a uniform circular motion on a smooth horizontal plane, and object B moves in a circular motion Under the action of a horizontal external force of 4.0 n, start from rest and follow the direction Move towards A. now both objects a and B start from position P at the same time Motion, when object a moves around point O for two weeks, a and B are just at point P Points meet. When a goes around for another half a circle, it meets B at Q. try A centripetal force of a body moving in a uniform circular motion

Set the radius r, period T and angular velocity of circular motion ω The acceleration of object B is a = f / M = 4.0 / 1.0 = 4 (M / S ^ 2) o'p = (1 / 2) at ^ 2 = (1 / 2) 4 (2t) ^ 2 = 8t ^ 2o'q = o'p + 2R = 8t ^ 2 + 2R = (1 / 2) a (2.5t) ^ 2 to obtain r = (9 / 4) T ^ 2 centripetal force F = M( ω)^ 2R=m(2π/T)^2R=1*(4*π^2/T^2)*(9/4)...