1. The waist length of the isosceles triangle with Girth 18 is x and the base length is y. find the functional relationship between Y and X and the value range of X 2. It is known that the area of the triangle formed by the graph of the first order function y = kx-2 and the x-axis and y-axis is 8, 3. As shown in the figure, ab = ad, ∠ B = ∠ D, find BC = DC 4.（xy^-1）^2×（-xy^4）^-1×（-y^2） 5.a/a+1-(a-2)/(a^2-1)÷(a^2-2a)/a^2-2a+1 The more answers, the better

If the intercept is 2, then the point with y axis is (0,2) and the area is 8, then the intersection point with X axis is (8,0) or (- 8,0)
3. No figure
4.xy^-4
5. Unclear inscription

Given that the circumference of isosceles triangle is 18, the base length is y, and the waist length is x, then the function analytic formula of Y and X is? 1、 If the image of a positive scale function passes through the point (2,3), then the analytic expression of the positive scale function is ﹤ uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu. 2、 The straight line y = 2x-5 is translated up by 4 units, and the analytic formula of the unit is obtained as ﹤ uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu.

The analytic formula of the function of base and waist: 2x + y = 18
Analytic formula of positive proportional function: y = (3-B) x / 2 + B
Analytical formula of straight line translation: y = 2x-1

Given that the circumference of an isosceles triangle is 20, the waist length is x, and the base length is y, then the functional relationship between Y and X is The value range of the independent variable x is .

∵2x+y=20，
ν y = 20-2x, i.e. x < 10,
∵ the sum of the two sides is greater than that of the third side
∴x＞5，
In conclusion, 5 ＜ x ＜ 10
So the answer is: y = - 2x + 20, 5 < x < 10

It is known that the circumference of isosceles triangle is 12 cm. If the base length is y cm, the waist length is x cm (1) Write the function relation between Y and X; (2) Find the value range of the independent variable x

(1) Y = 12-2x,
Therefore, the functional relationship between Y and X is: y = 12-2x;
(2) According to the meaning of the title:
2x＞y
x+y＞x ，
Namely
2x＞12-2x
12-2x＞0 ，
The solution is: 3 ＜ x ＜ 6
Therefore, the value range of independent variable x is 3 < x < 6

Given that the circumference of an isosceles triangle is 40 cm, what is the value range of the independent variable?

Two waists
So 2Y + x = 40
2y=-x+40
y=-x/2+20
The sum of the two sides is greater than the third
So y + Y > X
That is 2Y > X
So - x + 40 > X
X

The median line of the isosceles triangle AB = AC AC AC in ABC divides the circumference of the isosceles triangle into 15 and 6 parts, and calculates the waist length and base length of the triangle

Glad to answer for you!
This problem needs to be classified into two parts: the middle line on one waist divides the circumference of the isosceles triangle into 15 and 6, which may be 15 for the upper part and 6 for the lower part. It is also possible that the upper part is 6 and the lower part is 15
1. Let the waist length be X
3/2x=15
x=10
Bottom: 6-5 = 1
So the waist length of the isosceles triangle is 10 and the bottom length is 1
2. Let the waist length be y
3/2y=6
Y=4
Bottom: 15-2 = 13
So the situation does not hold

In an isosceles triangle, the middle line of one waist divides the circumference of the triangle into two parts, 12cm and 8cm. Then, the length of the bottom edge of the isosceles triangle is ()

Four
28/3

It is known that in the isosceles triangle ABC, ab = AC with a circumference of 16 cm. The median line BD on the edge of AC divides the triangle ABC into two triangles with a circumference difference of 1 cm Please help me with the homework tomorrow

Let AB = AC = x, then ad = CD = 1 / 2 x, BC = 16-2x (the first case), the triangle abd is 1 cm more than the triangle BDC, that is ab + ad = BC + CD + 1, (3 / 2 x) = 17 - (3 / 2 x), x = 17 / 3 (the second case) the triangle BDC is 1 cm more than the triangle abd, that is ab + AD +

In ABC, we divide it into two parts, which are equal to the circumference of BDAC

Assume that the waist length is a and the base length is B
Then a + A / 2 = 9 B + A / 2 = 8, a = 6 B-5
Or calculate 3 / b = 19 / a = 3 / b = 9 / A

As shown in the figure, the circumference of the isosceles △ ABC is 50cm, ad is the height on the bottom edge, and the circumference of △ abd is 40cm, then the length of ad is______ cm．

∵ ad is the height on the bottom edge,
∴BD=CD，
The circumference of ABC is 50cm,
∴AB+BD=1
2×50=25cm，
The circumference of abd is 40 cm,
∴AD=40-25=15cm．
So the answer is: 15

Given that the circumference of an isosceles triangle is 20, the waist length is x, and the base length is y, then the functional relationship between Y and X is______ The value range of the independent variable x is______ .