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Given the center line on the waist of an isosceles triangle, divide the circumference of the triangle into 9 cm and 15 cm, and calculate the length of each side of the triangle
Let the side length of both sides be 2x, the center line Z and the bottom y
Make equations according to conditions
1.4x+y=24
2.3x+z=15
3.x+y+z=9
Formula 2-3
2x-y = 6
Then add it to Formula 1 to get x = 5, y = 4
So the length of each side is 10.10.4
Hi I don't understand
In the isosceles triangle ABC, ab = AC, the median line BD on a waist divides the circumference of the triangle into two parts 15 and 6, and finds the three sides of the isosceles triangle
Let the waist length be x and the base length y
x+x/2=15、x=10.
x/2+y=5+y=6、y=1.
The three sides are 10, 10 and 1
In the isosceles triangle ABC, ab = AC, BD is the center line on the edge of AC. BD divides the circumference of △ ABC into two parts of 15cm and 9cm, and calculates the length of waist ab
Let AB = AC and BD be the median line
Let ad = X
There are two cases
(1)3x=9
X=3
The length of three sides is 6,6,12
If you don't agree with the topic, you will leave it
（2）
3x=15
X=5
The length of three sides is 10,10,4
AB=10
In an isosceles triangle, the middle line on one waist divides the circumference of the triangle into two parts: 21cm and 12cm
If the waist length is x and the base length is y, then according to the meaning of the title:
X+1/2X=21,1/2X+Y=12
Or x + 1 / 2x = 12,1 / 2x + y = 21
The solution is: x = 14, y = 5
Or x = 8, y = 17 (omit, because 8 + 8
If the middle line on the waist of an isosceles triangle divides the circumference of the triangle into two parts, 12cm and 21cm, then the length of the bottom edge of the isosceles triangle is___ .
Let the waist length of the isosceles triangle be xcm and YCM
X+x
2=12
Y+x
2 = 21 or
X+x
2=21
Y+x
2 = 12
X=8
Y = 17 or
x=14
y=5 ．
According to the trilateral relationship of a triangle, we know that 8, 8, 17 cannot form a triangle and should be omitted. Therefore, its bottom edge is 5cm
Therefore, fill in 5cm
If the median line on the waist of an isosceles triangle divides its circumference into two parts: 21cm and 12cm, then the base length of the triangle is
Let the waist length of the isosceles triangle be xcm and YCM
x+x/2=12
Y + X / 2 = 21 or
x+x/2=21
Y + X / 2 = 12
X=8
Y = 17 or
x=14
y=5．
According to the trilateral relationship of a triangle, we know that 8,8,17 cannot form a triangle and should be omitted. Therefore, its bottom edge is 5
It is known that: the circumference of isosceles triangle is 18 cm, and its base length is xcm, the functional relationship of waist length YCM about xcm is obtained, and the corresponding function image is drawn Write the value range of the independent variable! You don't want to draw the picture, just write the relationship of the image_ Haha~
2x+y=18
y=18-2x
X belongs to (4.5,9)
Because 2x > y (the sum of the two sides is greater than the third side)
The circumference of isosceles triangle is 18cm. If the waist length is YCM and the base length is xcm, try to write out the function relationship and write out the value range of the independent variable
Y = 1 / 2 (18-x) = 9-1 / 2x (x < 9) Note: the solution of independent variable: 2Y + x = 18 2Y > x (both sides and greater than the third side), the solution x < 9
The circumference of isosceles triangle is 18cm. If the waist length is YCM and the base length is xcm, try to write out the function relationship and write out the value range of the independent variable
Y = 1 / 2 (18-x) = 9-1 / 2x (x < 9) Note: the solution of independent variable: 2Y + x = 18 2Y > x (both sides and greater than the third side), the solution x < 9
The circumference of isosceles triangle is 18 cm, if the waist length is xcm, the base length is YCM 1. Find the function expression between Y and x 2. If the waist length is 7 cm, calculate the bottom side length 3. If the waist length is 5cm, find the area of the triangle
1.2x+y=18
So y = 18-2x
2. If the waist length is 7cm, then x = 7, then the bottom length y = 18-14 = 4cm
If the waist length is 5cm, then x = 5, then the bottom length is y = 18-10 = 8
Then the height is: √ (5? - 4?) = 3
So the area is: 1 / 2 × 5 × 3 = 15 / 2cm
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