If the two sides a, B of an isosceles triangle satisfy | 2a-3b + 5 | + (2a + 3b-13) 2 = 0, then the circumference of the isosceles triangle is______ .

If the two sides a, B of an isosceles triangle satisfy | 2a-3b + 5 | + (2a + 3b-13) 2 = 0, then the circumference of the isosceles triangle is______ .

∵|2a-3b+5|+（2a+3b-13）2=0，
Qi
2a−3b+5＝0
2a+3b−13＝0 ，
Qi
a＝2
b＝3 ．
When a = 2 is the base, the waist length is 3, 3, which can form a triangle, so the circumference is 2 + 3 + 3 = 8
When B = 3 is the base, the waist length is 2, 2, which can form a triangle, so the circumference is 3 + 2 + 2 = 7
Therefore, the circumference is 8 or 7
So the answer is: 8 or 7

Then the isosceles of the two sides of a + 2A + B are isosceles______ .

∵|a-b+1|+（2a+3b-13）2=0，
Qi
a−b＝−1
2a+3b＝13 ，
The solution
a＝2
b＝3 ，
Then the circumference of isosceles triangle is 2,2,3 or 3,3,2,
The circumference is 2 + 2 + 3 = 7 or 3 + 3 + 2 = 8

If a and B are two sides of an isosceles triangle, and | 2A + 2b-14 | + (3a-4b) 2 = 0, then the circumference of the triangle is___ .

|2a+2b-14|+（3a-4b）²=0
∴﹛2a+2b-14=0
3a-4b=0
∴a=4,b=3
When waist length is 4, circumference = 4 + 4 + 3 = 11
When waist length is 3, circumference = 4 + 3 + 3 = 10

It is known that AB is the length of two sides of an isosceles triangle, and ab satisfies the square of root A-2 + B - 6B = - 9. Find the circumference of the triangle

From A-2 > = 0,2-a > = 0, a = 2
Thus, B-3 = 0, B = 3
When a is the waist, the circumference is 2 + 2 + 3 = 7;
When B is the waist, the circumference is 3 + 3 + 2 = 8

It is known that AB is the side length of both sides of an isosceles triangle, and satisfies the equation of two 3a-6 + 3 roots 2-A = B-4, so we can find the perimeter and area of this isosceles triangle

Number under radical sign ≥ 0
∵ satisfy the equation of 2 roots 3a-6 + 3 roots 2-A = B-4
/ / 3a-6 ≥ 0 ① and 2-A ≥ 0 ②
① 3A ≥ 6 a ≥ 2
② A ≤ 2
① A = 2
Substituting into equation
0 + 0 = B-4, B = 4
The three sides of the isosceles triangle are 44 2
Perimeter
=4+4+2
=10
Pythagorean theorem:
The height corresponding to a base length of 2
=√(4²-1²)
=√15
The triangle area
=Bottom × height △ 2
=2×√15÷2
=√15

Given that both sides of an isosceles triangle AB satisfy 〝 2a-3b + 5  2A + 3b-13 = 0, calculate the circumference of the isosceles triangle

2a-3b+5=0
2a+3b-13=0
Adding two formulas
4a-8=0
A=2
4-3b+5=0
B=3
The perimeter can be 2 + 2 + 3 = 7 or 3 + 3 + 2 = 8

It is known that AB is the length of the two sides of an isosceles triangle, and ah, AB satisfies B = radical 3 minus a + root 2A minus 6 + 4. Find the circumference of this triangle and ask for the help of God

If B = √ (3-A) + √ (2a-6) + 4, then (3-A) ≥ 0 and (2a-6) ≥ 0, a ≤ 3 and a ≥ 3, i.e., a = 3, B = √ (3-A) + √ (2a-6) + 4 = 4. When a is the waist of an isosceles triangle, the circumference of the triangle is 3 × 2 + 4 = 6 + 4 = 10. When B is the waist of an isosceles triangle, the circumference of the triangle is 4 × 2 + 3 = 8 + 3 = 11

The circumference of an isosceles triangle is 18 and one side is 5

If 5 is waist length, the bottom edge is: 18-5-5 = 8 cm
If 5 is the bottom edge, the waist length is: (18-5) × 2 = 6.5cm

If the circumference of an isosceles triangle is 18 and the length of one side is 5, then the waist length is?

The waist length is 18-5 = 13, 13 / 2 = 13 / 2

Given that one side of an isosceles triangle is equal to 5 and the other side is equal to 6, then its circumference is equal to______ .

(1) When the three sides of the triangle are 5, 5, 6, the circumference is 16;
(2) When the three sides of a triangle are 5, 6, 6, the circumference of the triangle is 17;
So its circumference is 16 or 17
Therefore, fill in 16 or 17