In the isosceles triangle ABC, given Sina: SINB = 1:2 and base BC = 10, then the circumference of △ ABC is______ .

In the isosceles triangle ABC, given Sina: SINB = 1:2 and base BC = 10, then the circumference of △ ABC is______ .

Let BC = a, ab = C, AC = B
∵ Sina: SINB = 1:2
a:b=1:2,
∵ bottom BC = 10, i.e., a = 10, ᙽ B = 2A = 20
∵ the triangle ABC is an isosceles triangle, and BC is the bottom edge,
∴b=c=20
The circumference of △ ABC is 20 + 20 + 10 = 50
So the answer is 50

An isosceles triangle has a circumference of 28 cm, one side of which is 8 cm long. Find the length of the other two sides

If 8 is the bottom edge, the other two sides are 10, if 8 is the waist, the other two sides are 8 and 12 respectively

The circumference of the triangle is 50, the length of the first side is 5A + 3b, and the length of the second side is 2 times less than that of the first side by 2a-b + 1

If the length of the second side is x, then 2x + 2a-b + 1 = 5A + 3b, x = 3A / 2 + 2B + 1 / 2,
The third side length is 50 - (5a + 3b) - (3a / 2 + 2B + 1 / 2) = 101 / 2-13a / 2-5b

It is known that a and B are the two side lengths of an isosceles triangle, and a and B satisfy B = 4 + √ 3a-6 + 3 √ 2-A, then calculate the perimeter of the triangle

From b = 4 + √ 3a-6 + 3 √ 2-A,
We get {3a-6 ≥ 0
2-a≥0
A = 2, so B = 4,
Then, the circumference of the triangle is 4 + 4 + 2 = 10

Given that the area of a rectangle with one side length a and an isosceles triangle with a waist length a are equal, calculate the rectangle perimeter? A, 2A; B, 3A; C, 4a; D, 5A

Let the length of the other side of the rectangle be X
ax=1/2a^2
x=1/2a
So perimeter = 3A
Choose B

The circumference of a triangle is 5a-6b, the length of the first side is 2A + 3b, the length of the second side is 3a-2b, and the length of the third side is ()

The circumference of a triangle is 5a-6b, the length of the first side is 2A + 3b, the length of the second side is 3a-2b, and the length of the third side is (- 7b)

1. If the two sides of an isosceles triangle are 6 and 8, then the circumference is 2. If the two sides of an isosceles triangle are 3 and 6, then the circumference is

Let the length of the other side be X
The sum of the two sides of the triangle is greater than that of the third side, and the difference between the two sides is less than that of the third side
8-6<x<8+6
2<x<14
∵ is an isosceles triangle
ν x is taken as 6 or 8
The circumference is 6 + 6 + 8 = 20 or 6 + 8 + 8 = 22
Let the other side be X
6-3<x<6+3
3<x<9
∵ is an isosceles triangle
ν x is taken as 6
The circumference is 6 + 6 + 3 = 15

If a and B on both sides of an isosceles triangle satisfy | a-2b-3 | + (2a + B-11) (2a + B-11) = 0, what is its perimeter

From the equation | 2A + 2A + 2A + 2A + 2A + 2A + 2A + 2A + 2A + 2A + 2A + 2A + 2A + 2A + 2A + 2A + 2A + 2A + 2A + 2A + 2A + 2A + 2A + 2A + 2A + 2A + 2A + 2A + 2A + 2A + 2A + 2A + 2A + 2A + 2A + 2A + 2A + 2A + 2A + 2A + 2A + 2A
a-2b-3=0
2a+b-11=0
By solving the equations, a = 5, B = 1
Therefore: the waist is 5, and the bottom is 1. (when the waist is 1, it does not work because the sum of the two waists is less than the bottom)
So: the circumference of an isosceles triangle is 11

What is the circumference of an isosceles triangle whose two sides a and B satisfy | 2a-4 | + (2a + 3b-13) 2 = 0?

It is known that a and B on both sides of an isosceles triangle satisfy | 2a-4 | + (2a + 3b-13) 2 = 0
Then 2a-4 = 0, 2A + 3b-13 = 0
So a = 2, then 4 + 3b-13 = 0
B=3
The triangle is isosceles triangle
So the other side is 2 or 3
So the circumference is: 2 + 2 + 3 = 7 or 2 + 3 + 3 = 8

If a and B on both sides of an isosceles triangle satisfy | A-B + 2 | + (2a + 3b-11) 2 = 0, then the circumference of the isosceles triangle=______ .

∵|a-b+2|+(2a+3b-11)2=0,
Qi
a−b+2=0
2a+3b−11=0
A = 1, B = 3,
∵2a=2<3,
The length of the bottom edge is 1 and the length of the waist is 3,
ν perimeter = 3 × 2 + 1 = 7,
Therefore, the circumference of the isosceles triangle is 7
So the answer is: 7