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The absolute value of 2-radical-5 + (3-radical-5) is calculated as ()
2 - √ 50 ℅ absolute value of 2-radical 5 + (3-absolute value of root 5)
=√5-2+3-√5=1
Calculate the absolute value of the radical (3.14 - π) ^ 2-2 - π=
3.14＜π
√(3.14-π)^2-│2-π│
=（π-3.14）-（π-2）
=π-3.14-π+2
=-1.14
Calculate the 0 th power of (- 3) - the absolute value of root 27 + (1-radical 2) + 1 / (root 3 + root 2)
=1-3√3+√2-1+（√3-√2）/（√3+√2）（√3-√2） =√2-3√3+√3-√2 =4√3
How to calculate the absolute value of 3 times (2-root 3) times 8 / 27 - (negative 1 / 3) + root 3-2
=|(6-3 * root sign 3) * (2 / 3) + (1 / 3) + root sign 3-2 | = | 4-2 * root sign 3 + 1 / 3 + root 3-2 | = | 2 + 1 / 3-root 3 | = 2 + 1 / 3-root 3 |
[mathematical calculation problem] root 12 + 1 + (- 8's cube root) - (absolute value of radical 3-2) [mathematical calculation problem] Radical 12 + 1 + (- 8's cube root) - (absolute value of radical 3-2) Root number 5 (root 45 + root 20) - 3
（1）
Radical 12 + 1 + (- 8's cube root) - (absolute value of radical 3-2)
=2√3+1+(-2）-|√3-2|
=2√3-1-(2-√3) (√3
Calculation problem, root 81 + - 27 cube root + root (- 2 / 3) 2
Original formula = 9 + (- 3) + 2 / 3
=6+2/3
=20/3
Absolute value of radical 7 + 1 / 9 of radical + absolute value of radical-3 + cube root of minus 1 / 27 =?
Absolute value of root 7 + 1 / 9 of root + absolute value of radical-3 + cube root of minus 1 / 27
=Root 7 + 1 / 3 + root 3 - 1 / 3
=Radical 7 + root 3
Root 27 plus absolute value 1 - root 2 plus root 3 plus 1 / 2 root sign
Root 27 plus absolute value 1 - root 2 plus root 3 plus 1 / 2 root sign
=3 root 3 + root 2-1 + root 3 + root 2 / 2
=4 root number 3 + (3 root number 2-2) / 2
If you're satisfied,
2 / Radix 3-1 + Radix 27 - (Radix 3-1) 0 power
2 / Radix 3-1 + Radix 27 - (Radix 3-1) 0 power
=2 (radical 3 + 1) / 2 + 3 radical 3-1
=2 root sign 3 + 2 + 3 root sign 3-1
=5 root sign 3 + 1
The absolute value - 2 + (1 / 3) the power of the zeroth power of the root 9 + (- 1) of the negative first power multiplication (π - heel 2)
The absolute value - 2 + (1 / 3) the power of the zeroth power of the root 9 + (- 1) of the negative first power multiplication (π - heel 2)
=|-2|+(1/3)^(-1)×(π-2)^0-√9+(-1)^2010
=2+3×1-3+1
=2+3-3+1
=3
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