If x, y are real numbers and satisfy | x-3|+ If y + 3 = 0, then (x) y) The value for 2012 is______ .

If x, y are real numbers and satisfy | x-3|+ If y + 3 = 0, then (x) y) The value for 2012 is______ .

According to the meaning of the title:
x−3＝0
y+3＝0 ，
The solution is as follows:
x＝3
y＝−3 ．
Then (x
y）2012=（3
−3）2012=1．
So the answer is: 1

Known | 2012-a|+ If a − 2013 = a, then a-20122=______ .

From the meaning of the title: a-2013 ≥ 0,
A ≥ 2013 is obtained,
|2012-a|+
a−2013=a，
a-2012-a=-
a−2013，
a−2013=2012，
a-2013=20122，
a-20122=2013，
So the answer is: 2013

-2 + (- 2) 2012 square x (- 1 / 2) 2012 square + root - 8 cubic x (π - 2013)

There is something wrong with the expression
2012 square estimate you want to say the power of 2012
The third power of the root - 8 is that you want to say - 8 under the root of the third
If the above estimate is correct, then:
simple form
=-2 + (- 2 * - 1 / 2) to the power of 2012 + (- 2) x (π - 2013)
=-2+1-2π+4026
=4025-2π

Given that the real number a satisfies the absolute value 2010-a + Radix a-2011 = a, find the value of a-2010

/2010-a | + √ (a-2011) = 0 a-2011 ≥ 0 a ≥ 2011, so 2010-a

The real number a satisfies | 2009-a|+ A − 2010 = a, then the value of a-20092 is () A. 2008 B. 2009 C. 2010 D. 2011

According to the meaning of the title, a-2010 ≥ 0, that is, a ≥ 2010;
So | 2009-A | = a-2009,
A kind of
A − 2010 + | 2009-A = a, i.e
a−2010+a-2009=a，
Qi
a−2010=2009，
a-2010=20092，
∴a-20092=2010．
Therefore, C

Given that the real number satisfies the square of root sign (2009-x) + (a-2010) = a, find a-2009 ^ 2

(a-2010) meaningful
∴a-2010>=0
a>=2010
|2009-a|+√(a-2010)=a
a-2009+√(a-2010)=a
√(a-2010)=2009
a-2010=2009²
a-2009²=2010

Given that the real number x satisfies: | 2011-x | + x-2012 = x, find x-2012

∵x－2012≥0
∴ x≥2012
| 2011－x|＝x－2011
Then x-2011 + √ (x-2012) = X
√﹙x－2012﹚＝2011
∴ x－2012＝2011²

Given that the real number m satisfies the absolute value of 2008-m + root sign m-2009 = m, find the value of m-2008 square

Firstly, √ m-2009 is meaningful, M > = 2009
Then | 2008-m | = m-2008
Original formula √ m-2009 + m-2008 = m
√m-2009=2008
m-2009=2008^2
m-2008^2=2009

The real number a satisfies | 2011-a|+ a−2 012=3 a3 , find the value of a-20112

∵ a-2012 ≥ 0, that is, a ≥ 2012,
∴2011-a＜0，
∴|2011-a|+
a−2 012=a-2011+
a−2012=3 a3
=a，
Namely
a−2012=2011，
∴a-2012=20112，
Then a-20112 = 2012

Given that AB is a real number, root a-5 + root 10-2a = B + 4, find the square root of a + B

A + 2 a = 5 is equal to the root of a-5