How to divide 24 by root 3?

How to divide 24 by root 3?

24/√3
=8*3/√3
=8*(√3)^2/√3
=8√3

(7 Radix 54-3 Radix 24 + 24) divided by Radix 3

Put it away
(7 Radix 54-3 Radix 24 + 24) divided by Radix 3
=（21√6-6√6+24）÷√3
=21√2-2√2+8√3
=19√2+8√3;
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Radix 18 + Radix 3 - Radix 24 divided by Radix 3 Tomorrow's monthly exam. Can also give me more knowledge review Root 18 + root 3 divided by root 3 - root 24

Root 18 + root 3 divided by root 3 - root 24
=Root number 6 + 1-2 root sign 6
=1-radical 6

How to divide 10 roots into 24 by 2

10 roots 24 divided by 2
=20√6÷2
=10√6

Try to find 1 divided by root 2 plus 1 plus 1 divided by root 3 plus root 2 plus... Plus 1 divided by root 2012 and root 2011

1/（√2+1）+1/（√3+√2）+.+1/（√2012+√2011）
=（√2-1）/（（√2+1）（√2-1））+（√3-√2）/（（√3+√2）（√3-√2））+.+（√2012-√2011）/（（√2012+√2011）（√2012-√2011））
=（√2-1）+（√3-√2）+.+（√2012-√2011）
=√2012-1

1006% [root 1 * 2] + [root 2 * 3] + [root 3 * 4] + +【2011*2012】=

s=0;
for k=1:2011;
s=s+k*(k + 1)^(1/2);
End
s/1006
ans =
7.2184e+004

If M = root 2012 minus 1 / 2011, what is the fifth power of M minus the fourth power of 2m

If the numerator and denominator of M are multiplied by a root number 2012 plus 1, then M = root 2012 plus 1
In the following formula, we can merge the similar term (m-2) m ^ 4 into (root number 2012 minus 1) root sign m ^ 4
(root number 2012 minus 1) * m = 2011
The answer is 2011 * (Radix 2012 plus 1) ^ 3

Root sign (1 + 1 / 1 ^ 2 + 1 / 2 ^ 2) + root sign (1 + 1 / 2 ^ 2 + 1 / 3 ^ 2) +. + root sign (1 + 1 / 2011 ^ 2 + 1 / 2012 ^ 2)

Consider the general formula root sign (1 + 1 / N ^ 2 + 1 / (n + 1) ^ 2) whose denominator is [n (n + 1)] ^ 2 Molecular expansion n ^ 4 + 2n ^ 3 + 3N ^ 2 + 2n + 1 = (n ^ 2 + N + 1) ^ 2 the open radical of (n ^ 2 + N + 1) / [n (n + 1)] = 1 + 1 / n-1 / (n + 1) is expanded in this way to obtain 1 + 1-1 / 2 + 1 + 1 / 2-1 / 3.1 + 1 / 2010 + 1 / 2011 = 2

1. 1 / 7 + 28 - 700 =?, 2. 32-3, 1 / 2 + 2 =?

√(1/7)+√28-√700
=√(7/7²)+√(2²×7)-√(10²×7)
=(√7)/7+2√7-10√7
=(1/7+2-10)×√7
=(-55/7)×√7
=-55√7/7
√32-3√(1/2)+√2
=√(4²×2)-3√(2/2²)+√2
=4√2-3√2/2+√2
=(4-3/2+1)×√2
=(7/2)×√2
=7√2/2

(- 3 / 7 of the root of the - 4 quilt) (- 28 of the root sign of the 1 / 2 quilt) There are also the radical 24x (3 / 2 / 2 / 2 / 3) and the radical 18-2 / 2-2-2 / 8 + 1 process

[-4√(3/7)](-0.5√28)=2√12=4√3
2√24×(2√(8/3)/3)=4×8/3=32/3
√18-0.5√2-0.5√8+1=1.5√2+1