Given that / 2011-a / + radical (a-2012) = a, let B = a-2011? 2, calculate the value of B

Given that / 2011-a / + radical (a-2012) = a, let B = a-2011? 2, calculate the value of B

According to the meaning of the title:
a-2012≥0
∴a≥2012,
∴|a-2011|=a-2011,
It is known that:
a-2011+√(a-2012)=a
a-2012=2011^2,
a=2011^2+2012
∴b=a-2011^2=2012.

Calculate the value of (root 10 + 3) ^ 2013 * (Radix 10 - 3) ^ 2012

Note the merging of some special items
(Radix 10 + 3) ^ 2013 * (Radix 10 - 3) ^ 2012=
(Radix 10 + 3) ^ 2012 * (Radix 10 - 3) ^ 2012 * (Radix 10 + 3)
=[(root 10 + 3 * (Radix 10 - 3] ^ 2012 * (Radix 10 + 3)
=1 ^ 2012 * (root 10 + 3)
=(radical 10 + 3)

In the formula Radix 2013 * Radix 2010 * Radix 2011 * Radix 2012, which one do you estimate results in the greatest decrease of product due to the decrease of numerical value

It should be root 2010

/1 - root 2 / + / root 2 - root 3 / + / root 3 minus root 4 / +. + / root 2012 - root 2013 / = (result reserved Results the root sign was retained

|1-√2|+|√2-√3|+|√3-√4|+...+|√2012-√2013|
=(√2-1)+(√3-√2)+(√4-√3)+...+(√2013-√2012)
=√2013-1
If you don't understand, I wish you a happy study!

The 2012 power of (root 3 - root 2) is the 2013 power of (root 3 + root 2)

(Gen 3-gen 2) ^ 2012 * (Gen 3 + Gen 2) ^ 2012 * (Gen 3 + Gen 2)
=[(root 3-root 2) (root 3 + root 2)] ^ 2012 * (root 3 + root 2)
=1 ^ 2012 * (root 3 + root 2)
=Root 3 + root 2

The product of (2 + radical 3) to the power of 2013 and (2-radical 3) to the power of 2012 is

The original formula = (2 + root 3) 2012 power × (2-radical 3) 2012 power × (2 + root 3)
=[(2 + radical 3) × (2-radical 3)] 2012 power × (2 + radical 3)
=[4-3] 2012 power × (2 + radical 3)
=1 × (2 + radical 3)
=2 + radical 3

The 2012 power of root 2-root 3 is multiplied by the power of root 2 and root 3 to the power of 2013

The 2012 power of root 2-root 3 is multiplied by the power of root 2 and root 3 to the power of 2013
=The 2012 power of [(√ 2 - √ 3) × (√ 2 + √ 3)] is × (√ 2 + √ 3)
=1×﹙√2+√3﹚
=√2+√3

The 2012 power of (2-radix-3) is the 2013 power of (2 + radical 3) - 2-radical 3 / 2) - 1 -Root 3 / 2 that's absolute

The original formula = [(2 - √ 3) (2 + √ 3)] 2012 power * (2 + √ 3) - 2 * √ 3 / 2-1
=The 2012 power of (4-3) * (2 + √ 3) -√ 3-1
=The 2012 power of 1 * (2 + √ 3) -√ 3-1
=2+√3-√3-1
=1

The 2012 power of 1 (Radix 3-radix 2) times the 2013 power of (Radix 3-radix 2) is equal to? If the simplest quadratic root a + B times a-2b under the root sign and A-B + 3 under the root sign are the same kind of quadratic root, find the value of a B A + B is not a coefficient, but an unknown number at the top left of the sign. The first question is the 2012 power of (root 3 + root 2) times the 2013 power of (root 3-root 2)

Can you tell me if there is a plus sign
(root 3-root 2) 2012 power × (root 3 + root 2) 2013 power = [(root 3-root 2) × (root 3 + root 2)] 2012 power × (root 3 + root 2)
=[3-2] 2012 power × (root 3 + root 2) = 1, 2012 power × (root 3 + root 2) = root 3 + root 2

If a + 2B + 4 is opposite to each other under | A-B + 1 | + root sign, find the 2012 power of (a + b)

a-b+1=0
a+2b+4=0
The solution is a = - 2 b = - 1
(a+b)^2012=(-3)^2012=3^2012