It is known that the fraction 2x-3 is 3x-2. (1) when what is the value of X, the fraction is meaningless? (2) when what is the value of X, the value of the fraction is 0; (3) when what is the value of X, the value of the fraction is 1

It is known that the fraction 2x-3 is 3x-2. (1) when what is the value of X, the fraction is meaningless? (2) when what is the value of X, the value of the fraction is 0; (3) when what is the value of X, the value of the fraction is 1

1.2x-3=0
When x = 3 / 2, the fraction is meaningless
2.3x-2=0
When x = 2 / 3, the fractional value is zero
3.3x-2/2x-3=1
3x-2=2x-3
x=-1

When x = time division x + 1 / X squared - 1 is meaningless

When x = - 1

When x is the value, the fraction x squared plus 2x parts x is meaningless Hurry! X = - 2, right Whether there are errors in the process of solving problems: Because x x 1 ------------ = ------------ = ------------- x²+2x x(x+2) x+2 From x + 2 = 0, x = - 2 Please write the correct problem-solving process, fast ah, good bonus points, up to this 5 points, a total of 20 points Come on! Come on! Please tell me the reason for the error!!!

There are mistakes in your problem-solving process. You should not divide them into several parts. The correct solution is:
When the denominator is 0, the fraction is meaningless
X(X+2)=0
Then x = 0, or x + 2 = 0
That is, x = 0, or x = - 2

For the square - 4 of fraction x + 2 / x, what value does the fraction mean? When x takes what value, the value of fraction is zero?

According to the meaning of the title:
When x + 2 ≠ 0, X ≠ - 2
When x ≠ - 2, the fraction is meaningful
When x = 0, x = 0
x²=4 x≠-2
x=±2
∴x=2
When x = 2, the value of fraction is 0
It's made by hand!

When the square of fraction x-5x-6th of x-3x-4, what is the value of X, the fraction is meaningless? What is the value of X, the value of fraction = 0? Come on, tomorrow It's due

When x is 4 or - 1, the fraction is meaningless. When x is 6 or - 1, the fraction value = 0

Given the fraction (x-3) of fraction (x-5x + a), when x = 2, the fraction is meaningless, then what is the value of a? When a = 6, how many values of X make the fraction meaningless?

If the fraction is meaningless, the denominator is 0
Therefore, 2? 5 × 2 + a = 0
A=6
A=6
x²-5x+6=0
(x-2)(x-3)=0
x=2,x=3
So there are two

What is the value of X? The following fraction is meaningful: (1) 3 / (x + 2) (X-2) (2), the square of X + 1 / X - 5x + 6 (1) Question 1 (2) question 2

(1) The denominator of 3 / [(x + 2) (X-2)] cannot be equal to 0, that is, (x + 2) (X-2) ≠ 0, then: X ≠ - 2 and X ≠ 2
(2) The denominator of X + 1 / (x ^ 2-5x + 6) cannot be equal to 0, i.e. (x ^ 2-5x + 6) = (X-2) (x-3) ≠ 0, the result is: X ≠ 2 and X ≠ 3

Fractional equation: x square + 3 parts of 2x - x square - 2x parts 1 = 0 Urgent

3/(x²+2x)-1/(x²-2x)=0
3/[x(x+2)]-1/[x(x-2)]=0
Multiply both sides by X (x + 2) (X-2) to get 3 (X-2) - (x + 2) = 0
That is, 2x-8 = 0
So x = 4
Substituting x = 4 into x (x + 2) (X-2) is not 0, so x = 4 is the root of the original equation

When x is the value, the square of fraction 2x + 1 / 1-x is 0

(1-x)/(2x^2+1)=0
So: 1-x = 0
X = 1

When x is the value, the square of fraction 3 + 2x times x + 1 is positive

(x^2+1)/(3+2x)>0
Because x ^ 2 + 1 > 0
3+2x>0
2x>-3
x>-3/2