If the value of fraction (x + 1) (X-2) is equal to 0, find the value of X

If the value of fraction (x + 1) (X-2) is equal to 0, find the value of X

-In fact, if the numerator is zero, we can calculate the positive and negative 2. At the same time, because the denominator cannot be zero, X is not equal to 2, so x is equal to - 2

Can the value of fraction x + 1 / x? - X-2 be equal to 0?

No
If x + 1 / x? - X-2 = 0
Then the molecule x + 1 = 0 x = - 1
When x = - 1, the denominator x? - X-2 = 1 + 1-2 = 0 is meaningless
So the value of fraction x + 1 / x? - X-2 cannot be equal to 0

Given the fraction x? - 2x-3 / x? + 2x, when x is taken, the value of (1) is positive, and (2) its value is negative

(x-3)(x+1)/(x+2)x
therefore
①x

When the value of fraction x-2-3 is positive, the range of X is () and when the value of fraction x-2x + 1 / 1 is negative, the range of X is ()

X

The value of 2x - 1 of fraction x 2 is negative. Find the value range of X

2x-1<0
x²≠0
Ψ x < 1 / 2 and X ≠ 0

Given x + 1 / x = 2, find the value of the fraction (x? 2 + 2x + 1) / (4x? - 7x + 4)

x+1/x=2
Both sides are multiplied by X and the term is shifted to obtain x? - 2x + 1 = 0
That is (x-1) 2 = 0
The solution is x = 1
Put in the fraction,
（x²+2x+1）/（4x²-7x+4）
=(1+2+1)/(4-7+4)
=4

Given x + 1 / x = 2, find the value of fraction (x ^ 2 + 2x + 1) / (4x ^ 2-7x + 4)

（x^2+2x+1）/（4x^2-7x+4）
Divide the numerator and denominator by X at the same time
The original formula = (x + 2 + 1 / x) / (4x-7 + 4 / x)
=[(x+1/x)+2]/[4(x+1/x)-7]
=4/(8-7)
=4

Given that 1 of X + x = 2, find the fraction 4x 2 - 7x + 4 / x 2 + 2x + 1

(x²+2x+1)/(4x²-7x+4)
=(x +2 +1/x)/(4x -7 +4/x)
=[(x+ 1/x)+2]/[4(x +1/x) -7]
=(2+2)/(4×2-7)
=4

Given x + 1 / x = 2, find 4x? - 7x + 4 / x? + 2x + 1

x+1/x=2
x²+1=2x
x²-2x+1=0
(x-1)²=0
X=1
4x²-7x+4/x²+2x+1
=1-7+4/1+2+1
=-2/4
=-1/2

Given that X-1 = 2 √ 2, find the value of the fraction (x? - 2x-9) / (2x? - 4x-l5)

x－1＝2√2
The square is x? 2x + 1 = 8
∴x²-2x=7
﹙x²－2x－9﹚/﹙2x²－4x－l5﹚
=（7-9）/(2×7-15)
=2