If the value of fraction 3x + 4 / X-2 is 0, then x =? 2. If the square of X-1 / x-2x + 1 is 0, then x =? 2? 3. When x?, the value of fraction 1 / 2-3x is negative

If the value of fraction 3x + 4 / X-2 is 0, then x =? 2. If the square of X-1 / x-2x + 1 is 0, then x =? 2? 3. When x?, the value of fraction 1 / 2-3x is negative

1. Because the value of fraction 3x + 4 / X-2 is 0
So 3x + 4 = 0
3x=-4
x=-4/3
I don't understand if I lost 2
3. Because the value of fraction 1 / 2-3x is negative
So the numerator of a fraction is different from the denominator
So 2-3x

When x is the value of X, the following fraction is meaningful: (1) X-2 x squared-6 (2) 3x squared | - 7 (3) x squared x-11-2x x-3 (4) 5-x-1

(2)x≠0(3)

When x is taken, the square of fraction 3x - 12 / the square of X + 4x + 4 makes sense

Denominator is not equal to 0
x²+4x+4≠0
(x+2)²≠0
x+2≠0
x≠-2

When x is taken, the following fraction is meaningful 1 / 3x 1 / 3-x x X-5 / 3x + 5

Only when the denominator of a fraction is not 0 is a fraction meaningful
When 3x ≠ 0, that is, X ≠ 0, fraction 1 / (3x) is meaningful;
When 3-x ≠ 0, that is, X ≠ 3, fraction 1 / (3-x) is meaningful;
When 3x + 5 ≠ 0, that is, X ≠ - 5 / 3, the fraction (X-5) / (3x + 5) is meaningful

When y = 2-3x fraction X-1, what value of X is: 1. Y is positive; 2. Y is negative; 3. Y is 0. 3. Fraction is meaningless

When y = (x-1) / (2-3x), which value of X is taken: (1) y is positive; (2) y is negative; (3) y is 0; (4) fraction is meaningless
(1) Let (x-1) / [2-3x) > 0, then (x-1) / [3 (X-2 / 3)]

It is known that the fraction (x-1) (x-4) is 3x-4, (1) when x = what value, the fraction is meaningful, (2) when x = what value, the fraction is equal to 0

The denominator cannot be zero, so when x ≠ 1 and X ≠ 4, the fraction is meaningful
When the molecule is zero, the sub fraction is equal to 0, that is, when x = 4 / 3, the fraction is equal to 0

Proof: no matter what value x is, the fraction x ^ 2-3x-4 / x ^ 2-4x + 6 is always meaningful emergency

(x^2-3x-4)/(x^2-4x+6)
=(x-4)(x+1)/(x^2-4x+4+2)
=(x-4)(x+1)/[(x-2)^2 +2]
(X-2) ^ 2 + 2 ≥ 2 on denominator
So whatever the value of X, the fraction always makes sense

No matter what number x takes, it must be meaningful to divide the square of x-3x-4 by the square of x-4x + 6

To have a meaningful fraction, the denominator cannot be equal to zero
∵x²-4x+6=x²-4x+4+2=(x-2)²+2＞0
Whatever number x takes, the square of fraction X - 3x - 4 divided by the square of X - 4x + 6 must be meaningful

1. When x = 2, fraction 2a-3x / 4x + A is meaningless. When we find the value of X, let the value of fraction be zero

When x = 2, fraction 2a-3x / 4x + A has no meaning
That is 4x + a = 0
2*4+a=0
a+8=0
a=-8
The value of the fraction is zero
That is, 2a-3x = 0
-8*2-3x=0
3x=-16
x=-16/3

When x = 2, fraction 4x − 1 3x − A is meaningless. Find the value of A

From the meaning of the title: 3x-a = 0,
Then we substitute x = 2 to get 6-A = 0,
A = 6