If a ≤ 1, then (1-A) 3 is reduced to___ .

If a ≤ 1, then (1-A) 3 is reduced to___ .

∵a≤1，
Qi
(1-a)3=（1-a）
1-a．
So the answer is: (1-A)
1-a．

Reduction: radical-a Cube / b (> 0)

√[（-a）³/b]
=[√（-a）³]/(√b)
={√[（-a）³b]}/b

Simplify the cube-a of root-a times 1 / 2 of radical-a To be specific,

The cube-a of the root-a times 1 / 2 of the root-a
=(-a)√(-a)-a×√(-a)/(-a)
=(-a)√(-a)+√(-a)
=(1-a)√(-a);
It's my pleasure to answer your questions and skyhunter 002 to answer your questions
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If a is less than 0, then the - a cube under the radical is simplified

In fact, negative numbers can't have roots
If we want to change it, we will multiply the three - A in the root sign, that is, the root sign a ^ 2 * - A
So a ^ 2 comes up with a radical - A
At this point, if you've learned imaginary numbers
That's a (radical a) I
I haven't learned the answer above

Radical 4A ^ 2B ^ 3 Reduction to the simplest quadratic radical

Radical 4A ^ 2B ^ 3
=2|a|b√b
Obviously, B ≥ 0

First simplify, then evaluate: (A-2 a2+2a-a-1 a2+4a+4)÷a-4 A + 2, where a= 2-1．

Original formula = [A-2
a(a+2)-a-1
(a+2)2]•a+2
A-4
=a2-4-a2+a
a(a+2)2•a+2
A-4
=a-4
a(a+2)2•a+2
A-4
=1
a(a+2)．
When a=
When 2-1, the original formula = 1
(
2-1)(
2-1+2)=1．

1. First simplify and then evaluate: the root of a is 1-A: the third power of root 4A - the square root of a is 4, where a = 1.21 2. Given that the root of a is 3% of a + 3% of a + 27a = 15, calculate the value of A 3. Solve the equation: root 50-x = root 0.08 + 5 / 24, root 18 / 1 4. Let radical 2 = A and radical 3 = B, please use the integral formula about a and B to express Radix 12-1 / 18 - (Radix 72-radix 27) 5.3 2-3 parts of roots 54 + 3 parts of 3 parts 8 parts of 3 parts 6.2c square B the third power of root a B the third power of 8C (a > 0, b > 0) 7. Square root-2 (x + 3) (what value of X is meaningful) 8. The root of X-1 is x + 2 It's done. Add to 80

First of all, your expression is not very clear. I understand it as the following formula, which is not put forward,
1, the original formula = a √ (1 / a) - 1 / A * √ 4A ^ 3-A ^ 2 * 4 / √ a ^ 3 = √ A-2 √ A-4 √ a = - 5 √ a,
When a = 1.21, the original formula = - 5 √ 1.21 = - 5 * 1.1 = - 5.5
2, a √ (3 / a) + 3 √ A / 3 + √ 27a = √ 3A + √ 3A + 3 √ 3A = 5 √ 3A = 15, then a = √ 3,
3,5√2-x=0.2√2+0.8√2=√2,x=4 √2,
4,√12-√1/18-(√72-√27)=2√3-(1/6)*√2-6√2+3√3=5√3-(37/36)*√2
=5a-(37/36)*b
5,3√(2/3)-(2/3)*√54+(3/2)√(8/3)=√6-2√6+√6=0,
6. Can't read formula
7, - 2 (x + 3) ^ 2 ≥ 0, then (x + 3) ^ 2 ≤ 0, ν x = - 3,
To make the original formula meaningful, x + 2 ≥ 0 and X + 1 ≠ 0, that is, X ≥ - 2 and X ≠ - 1

Simplify the square of a + 1 / A + 4A + 4 divided by (a-1-a + 3 / 1), where a = 2 + radical 3

(a + 1) (square of a + 4A + 4) divided by [A-1 - (a + 1) 3]
=(a + 1) divided by [(a + 1) (a 2 - 4)]
=(a + 1) (a + 2) 2 * [(a + 2) (A-2)] (a + 1)
=(A-2) (a + 2)
=(2 + root 3 - 2) cent (2 + root 3 + 2)
=(root 3) (4 + root 3)
=3 / 3 (4 pieces, 3 + 3)

Radix (4-A) plus Radix (9-4a) minus Radix (1 + 2a) plus Radix (- a squared) Can't use the root sign!

Because the root is greater than or equal to 0
So - A ^ 2 ≥ 0
Because a ^ 2 ≥ 0
So a = 0
√(4-a)+√(9-4a)-√(1-2a)+√-a^2=√4+√9-√1+√0=2+3-1+0=4

1-4a + 4A square under 2A + radical How to discuss classification without hidden conditions

It's not right upstairs (~ stands for square)
1-4a+4a~=(1-2a)~
So 1-4a + 4A ~ = absolute value of (1-2a) ~ = 1-2a under radical sign
When 1-2a1 / 2
Original formula = 2A + root sign (1-2a)~
=2a+2a-1
=4a-1
When 1-2a > 0, a