The point P (2a-1, 3a-9) is in the fourth limit. Dissolve the square - 6a of root a + the square - 4A + 1 of root 4a

The point P (2a-1, 3a-9) is in the fourth limit. Dissolve the square - 6a of root a + the square - 4A + 1 of root 4a

2a-1 > 0 and 3a-9

When a = 1 / Radix 3, find 1-2a + a square / a square - 1 + 2A square - 4A / a square - A-2 A Square-1 + 2A square-4a / a square-a-2 A Square-1 and + 2A square-4a / a square-a-2 are not linked together

The original formula = (A-1) 2 / (a + 1) (A-1) + 2A (A-2) / (a + 1) (A-2)
=(a-1)/(a+1)+2a/(a+1)
=(3a-1)/(a+1)
=(√3-1)/(√3/3+1)
=3(√3-1)/(3+√3)
=2√3-3

Cube root minus 1 / 27=_____ (- 1 / 3) quadratic=______

Cube root minus 27 1 = cube root (- 1 / 3) = - 1 / 3
(- 1 / 3) quadratic = 1 / 9

Cube root 19 / 27-1 - radical 1 + 9 / 16

Cube root 19 / 27-1 - radical 1 + 9 / 16
=Cube root - 8 of 27 - 25 of 16
=-2 / 3-5 / 4
=-23 out of 12

If the square + 1 of 3 / 2 root sign 4A and the square - 1 of 2 / 3 root sign 6A are the same kind of quadratic root, then a=

The same kind of quadratic root must be the same number of square root: 4A ^ 2 + 1 = 6A ^ 2-1, a = ± 1

It is known that the root sign of the simplest quadratic radical (2 * A's Square - a) and the root sign (4a-2) are the same kind of quadratic root. The solution of the quadratic equation (A-2) x of X + 13 / 4x-5 / 4 = 0 is obtained

From the meaning of the title
2A squared - a = 4A - 2
The solution is a = 2 or a = 1 / 2
Because the equation about X (A-2) the square of X + 13 / 4x-5 / 4 = 0 is a quadratic equation of one variable
So a = 1 / 2, a = 2, let go
So the original equation is - 3 / 2x square + 13 / 4x - 5 / 4 = 0
By solving this equation, x = 1 / 2 or x = 5 / 3
The key to solve this problem is to find the value of a according to the known conditions
2. Because this problem is a quadratic equation of one variable and the coefficient of the highest term (quadratic term) contains an unknown number a,
Therefore, it is necessary to judge whether or not a value should be omitted
3. A general quadratic equation of one variable is obtained by substituting the value of a into the equation

If the simplest quadratic radical 3a-b, the root sign 4A + 3b, and the square - B of root 2Ab, the third power + 6B of square - B, are the same kind of quadratic radical

So the number of times before the root is two
So 3a-b = 2
b=3a-2
The simplest radical is the same kind of radical
So the numbers under the root sign are equal
√(2ab²-b³+6b²)
=|b|√(2a-b+6)
So 4A + 3B = 2a-b + 6
a+2b=3
Put B = 3a-2 in
a+6b-4=3
So a = 1
b=3a-2=1

If the square - 2 of the simplest quadratic radical - 1 / 2 times the root sign 1 + A and the square - 2 of the triple root sign 4A are the same kind of quadratic radical, find the value of A

From - (1 / 2) √ (1 + a) and 3 √ (4a? - 2) are quadratic roots of the same kind,
There must be 1 + a = 4A? - 2
4a²-a-3=0
(a-1)(4a+3)=0
a1=1,a2=-3/4.
When A1 = 1, it is the simplest quadratic radical √ 2
When a 2 = - 3 / 4, √ 1 / 4 is not the simplest quadratic radical
∴a=1.

What is the square of the cubic root 3, 3 times 2, the cube of 3, and 1 / 3 of the cubic root ╮(╯▽╰)╭~★

The square of cubic root 3 = 3 √ 9
, three times root 3 times 2, = 3 √ 6
Cube of cubic root 3 = 3
, one third of the third root = one third of √ 9

The square root of a is the product of 8A plus the cube of 3A root 50A

The cube of a ^ √ 8A + 3a √ 50A = 2A ^ √ 2A + 15A ^ √ 2A
From √ 8a, we know that a is positive, so the cube of 3A √ 50A is not written as - 15A ^ √ 2A