We know that the square of the root (2x-y) is 1 and the cubic root (x-2y) is 1 According to the meaning of arithmetic square root, from the root sign (2x-y) 2 = 1, get (2x-y) 2 = 1, get 2x-y = 1. ① according to the definition of cube root, cube root (x-2y) 3 = - 1, get x-2y = 1; ② get 3x + 3Y = 2 and get X-Y = 2 / 3 from ① + ②. What is the wrong step in the process of solving the problem? What steps does it neglect? Try to analyze and write the correct solution process

We know that the square of the root (2x-y) is 1 and the cubic root (x-2y) is 1 According to the meaning of arithmetic square root, from the root sign (2x-y) 2 = 1, get (2x-y) 2 = 1, get 2x-y = 1. ① according to the definition of cube root, cube root (x-2y) 3 = - 1, get x-2y = 1; ② get 3x + 3Y = 2 and get X-Y = 2 / 3 from ① + ②. What is the wrong step in the process of solving the problem? What steps does it neglect? Try to analyze and write the correct solution process

The error is (2x-y) 2 = 1
2x-y = 1
2x-y = 1 can also be equal to - 1

Given the square of the root sign (2x-y) = 1, and the cubic root of the cube (x-2y) = 1, find the value of X-Y According to the meaning of arithmetic square root, from the root sign (2x-y) 2 = 1, we get (2x-y) 2 = 1, and then we get 2x-y = 1. ① according to the definition of cube root, cube root (x-2y) 3 = - 1, x-2y = 1; ② from ① + ②, we get 3x + 3Y = 2, and we get X-Y = 2 / 3 What is the wrong step in the process of solving the above problem? What does it ignore? Try to analyze and write the correct solution process

Error in the first step: root sign (2x-y) 2 = 1, get (2x-y) 2 = 1, get 2x-y = 1 (wrong here, should be positive and negative 1) correct solution: according to the meaning of the square root of arithmetic, from the root sign (2x-y) 2 = 1, get (2x-y) 2 = 1, get 2x-y = ± 1

Given that the square of the root sign (2x-y) is 1, the cubic root of the cube (x-2y) = - 1, and X ≠ y, find the value of 3x + y of X-Y,

From the square of root sign (2x-y) = 1, the square of (2x-y) is 1, and then 2x-y = 1, 2x-y = - 1
The cubic root (x-2y) = - 1, x-2y = - 1
From (1) and (2), we get the solution of 2x-y = 1 and x = 1, 2x-y = - 1 and x = - 1 / 3
X-2y = - 1, y = 1, x-2y = - 1, y = 1 / 3
Because x ≠ y, y = 1 / 3, x = - 1 / 3
So X-Y is 3 x + y = 1

It is known that x + 2 is the arithmetic square root of X + 2 under a = 4x-y-3 root sign, B = 3x + 2y-9 power root, 2-y is the cube root of 2-y, try to find the cube root of a + B

According to the meaning of the question, 4x-y-3 = 2,3x + 2y-9 = 3, the solution is x = 2, y = 3, a = 2 times root (x + 2) = 4 = 2, B = 3 times root (2-y) = 3 times radical-1 = - 1 ± √ (a + b) = ± √ (2-1) = ± 1 (2-1) = ± 1 (2-1) = (± 3) 2 = 9, and the solution is a = 5B + 1 = (± 5) &

Known: M = (4x-y-3) under the root sign x + 2 is the arithmetic square root of X + 2. N = 3x + 2y-9, 2-7 is the cube root of 2-y. find the square root of M + n

The square root of arithmetic is square root
So 4x-y-3 = 2
y=4x-5
Cube root is cubic root
So 3x + 2y-9 = 3
So 3x + 8x-10-9 = 3
X=2
y=4x-5=3
So m = √ 4 = 2
n=³√(-1)=-1
So m + n = 1
The square root of M + n = - 1 and 1

It is known that the square root of X-Y is the positive and negative root, and the cube root of 2x + y + 7 is 2. Find the arithmetic square root of X-Y to the 2nd power of Y

The square root of X-Y is a positive and negative root sign 2  X-Y = 2
The cube root of 2x + y + 7 is 2 ℅ 2x + y = 1
X = 1, y = - 1
√﹙x²－y²﹚＝√0=0

Given that y = radical 3-x + radical x-3-2, find the cube root of the x-th power of Y

Y = radical 3-x + Radix x-3-2 is meaningful
Then 3-x ≥ 0, x-3 ≥ 0
Then 3 ≥ x ≥ 3
Then x = 3
Then y = 0 + 0-2 = - 2
The cube root of - 2 = - 2

Given that n is a positive integer and the 2n power of X is equal to 4, find the value of the 2nd power of (3x to the 3N power) minus the 2n power of 13 (the 2nd power of x)

X^2N=4
Original formula = 9x ^ 6n-13x ^ 4N
=9(X^2N)^3-13(X^2N)^2
=9×4^3-13×4^2
=368

Given that n is a positive integer and X 3N = 2, find the value of (3x3n) 3 + (- 2x2n) 3

The original formula = 27 (x3n) 3-8 (x3n) 2 = 27 × 8-8 × 4 = 184

Given that n is a positive integer and the 2nd power of (x to the nth power) is 9, find the 2n power value of (1 / 3x to the 3N power) - 3 (to the 2nd power of x)! I'm a math idiot Everybody Please, OTZ

(the nth power of x) 2 = 9, that is, the 2n power of x = 9 (the 3N power of 1 / 3 x) 2 - 3 (x 2) to the 2n power = (1 / 3) 2 (x to the 2n power of x) 3 - 3 (x to the 2n power of x) 2 = (1 / 9) x9? - 3x9? = 9? - 2x9? = - 162