It is known that the solution of the system of equations 2x-4y = 6-2m, 3x + 5Y = 10 + 3M on X, y satisfies the equation x + 3Y = 14 + 7m, and find the value of M To process

The solution of 2x-4y = 6-2m, 3x + 5Y = 10 + 3M satisfies the equation
X = - 3Y + 14 + 7m into 2x-4y = 6-2m, 3x + 5Y = 10 + 3M
The - 6y + 28 + 14m-4y = 6-2m
-9Y+42+21M+5Y=10+3M
5Y=11+8M 20Y=44+32M …… （1）
4Y=32+19M 20Y=160+40M…… （2）
（1）-（2）
0=-116-8M ,M=-14.5

If x = 2 is the solution of the equation 2x + 3m-1 = 0 about X, what is the value of M?

X = 2 is the solution of the equation 2x + 3m-1 = 0 about X
be
2x2+3m-1=0
4+3m-1=0
3m=-3
m=-1

If the equation 2X-4 = 3M and X + 2 = m have the same solution, then the value of M is () A. 10 B. -8 C. -10 D. 8

From 2X-4 = 3M, x = 3M + 4
2. From x + 2 = m, x = m-2
From the meaning of the title, 3M + 4
2=m-2
The result is: M = - 8
Therefore, B

Given that x = - 3 is the solution of the equation 2x-7m = - 5-2x on X, then the value of m to the power of 2008-m to the power of 2009 is

X = - 3 is the solution of the equation 2x-7m = - 5-2x on X
－6－7m=－5＋6
m=－1
The 2008 power of M - the 2009 power of M = 1 - (- 1) = 2

Given that x satisfies the equations 2x-3y + 4m = 11 and 3x + 2Y + 5m = 21, y satisfies x + 3Y + 7m = 20, then the value of M is () A0 B1 C2 D3

Hope to help you Mei In this paper, the results show that, for the system ╭ 2x-3y = 11-4m, ① 3x + 2Y = 21-5m, ② x + 3Y = 20-7m, ③ ① + ③, 3x = 31-11m, that is, x = (31-11m) / 3 ① * 2 + ② * 3, and 13X = 22-8m + 63-15m, i.e., x = (85-23m) / 13, so (31-11m) / 3 = (85-23m) / 13 (31-11m) = 3 (8

If M and N are two of the equations x2-2x-1 = 0 and (7m2-14m + a) (3n2-6n-7) = 8, then the value of a is equal to______ .

∵ m and N are two of the equations x2-2x-1 = 0,
∴m2-2m=1，n2-2n=1①，
∵ the original formula = (7m2-14m + a) (3n2-6n-7) = 8, namely [7 (m2-2m) + a] [3 (n2-2n) - 7] = 8,
Substituting ① into (7 + a) (3-7) = 8, a = - 9
So the answer is: - 9

It is known that m and N are two of the equations x? - 2x-1 = 0, and (7m? - 14m + a) (3N? 6n-7) = 8, then how much the value of a is equal to should be very detailed

If Mn is the two roots of the equation x ^ 2-2x-1 = 0, then there are m ^ 2-2m-1 = 0 and n ^ 2-2n-1 = 0
Then 3N ^ 2-6n-7 = 3 (n ^ 2-2n) - 7 = 3 * 1-7 = - 4
So there is 7m ^ 2-14m + a = 8 / (- 4) = - 2
7(m^2-2m)+a=-2
7*1+a=-2
a=-9

Given that m and N are two of the equations x * 2-2x-1 = 0, find the value of the algebraic expression (7m * 2-14m-3) (3N * 2-6n + 500)

From the meaning of the title:
m^2-2m-1=0,
——》7m^2-14m-3=7(m^2-2m-1)+4=4；
n^2-2n-1=0,
——》3n^2-6n+500=3(n^2-2n-1)+503=503；
——》Original formula = 4 * 503 = 2012

If M and N are two of the equations x2-2x-1 = 0 and (7m2-14m + a) (3n2-6n-7) = 8, then the value of a is equal to______ .

Let m, n be two of the equations x minus 2x minus 1 equal to 0, and (7m minus 14m plus a) (3N minus 6N minus 7) = 8, calculate the value of A

According to the meaning of the title, m * 2-2m-1 = 0, n * 2-2n-1 = 0, then 7m * 2-14m-7 = 0, 3N * 2-6n-3 = 0, namely 7m * 2-7m = 7, 3N * 2-6n = 3, so (7 + a) (3-7) = 8, a = - 9

It is known that the solution of the system of equations 2x-4y = 6-2m, 3x + 5Y = 10 + 3M on X, y satisfies the equation x + 3Y = 14 + 7m, and find the value of M To process