If the solution of equation 3 (x-1) + 8 = 2x + 3 is the same as that of equation x + K / 5 = 2-2x / 3, find the value of K

If the solution of equation 3 (x-1) + 8 = 2x + 3 is the same as that of equation x + K / 5 = 2-2x / 3, find the value of K

3(x-1)+8=2x+3
3x-3+8=2x+3
x=-2
Because the solutions of the two equations are the same, the K value can be obtained by substituting x = - 2 into the second equation
x+k/5=2-2x/3
-2+k/5=2-2*(-2)/3
k/5=2+4/3+2
k=80/3
So k = 80 / 3

If the solution x = 1 of the equation 2x-k-2 x-2k = 1, then the value of K is

Replace x = 1 into the original equation.. (2x-k) / 3 - (x-2k) / 2 = 1
(2*1-k)/3 - (1-2k)/2 = 1
2(2-k) - 3(1-2k) = 6
4-2k-3+6k=6
4k=5
k=5/4

When k is taken, the solution of 2k-1 / 3 = kx-1 / 2 is the same as that of 2x-1 = 5-x

3x=6
X=2
(2k-1)/3=(2k-1)/2
2k-1=0
k=1/2

When k goes to what value, the solution of 2k-1 = kx-1 is the same as that of 2x-1 = 5-x

2x-1=5-x
X=2
Replace x = 2 into 2k-1 = kx-1
(2k-1)/3=(2k-1)/2
K = 1 / 2 of the solution

Given the equation about X, 3x minus 2x is equal to 1, which is the same as that of 3 minus m equal to 2x. Try to find the solutions of the two equations and the value of M

For the equation of X, 3x-2x = 1 x = 1 (the solution of this equation is x = 1, 3-m = 2x is the equation about X, and the solution of the equation is x = 1. Replace x = 1 into the original equation: 3-m = 2, M = 1. Therefore, for the equation of X, the solution of both equations is x = 1; the value of M is 1

2X plus 1.2 equals 3x minus 0.3. How to solve this equation?

2x+1.2=3x-0.3
3x-2x=1.2+0.3
x=1.5

The equation 2x square minus 3x plus m is equal to one root of 0 which is twice the other. Find the value of M

2x²-3x+m=0
If one is x, then the other is 2x
According to the relationship between root and coefficient: x + 2x = - B / a = - (- 3) / 2 = 3 / 2
x=1/2
So 2x = 1
Because of the relationship between the basis and the coefficient: X * 2x = C / a = m / 2
So 1 / 2 * 1 = m / 2
M=1

It is known that the solutions of the equations 3x-2m + 1 = 0 and 2-m = 2x on X are opposite to each other. Try to find the solutions of these two equations and the value of M

3x-2m+1=0,
The solution is: x = 2 m
3,
2-m=2x,
The solution is: x = 2 − M
2,
According to the meaning of the title: 2m − 1
3+2−m
2=0,
The denominator is: 4M-2 + 6-3m = 0,
The solution is: M = - 4,
The solutions of the two equations are - 3 and 2.5 respectively

It is known that the solution of equation 3x minus 1 is equal to x + 5, which is 2 times larger than that of equation 2x minus 4K equal to x + 3, so find the value of K It is known that the solution of equation 3x minus 1 is equal to x + 5, which is 2 times larger than that of equation 2x minus 4K equal to x + 3, so find the value of K

3x-1=x+5;
2x=6;
x=3;
2x-4k=x+3;
x=4k+3;
3-2=4k+3;
1=4k+3;
4k=-2;
k=-1/2;
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When a is the value, the equation x? 2x-3a = 0 and equation 2x? 3x + a = 0 have a common root

Let common be m
Then M 2 - 2m-3a = 0 (1)
2m²+3m+a=0 (2)
(1)+(2)×3
7m²+7m=0
m=0,m=-1
If M = 0, then a = 0
If M = - 1, then a = 1