When m=______ The equation 2x with respect to X x−3＝2+m X − 3 produces root augmentation

When m=______ The equation 2x with respect to X x−3＝2+m X − 3 produces root augmentation

By multiplying (x-3) on both sides of the equation, 2x = 2 (x-3) + M,
∵ the original equation has an increasing root,
The simplest common denominator x-3 = 0, that is, the augmented root is x = 3,
Substituting x = 3 into the integral equation, M = 6
So the answer is: 6

If the equation 2x / (x-1) + (3-m) / (2-x) of X has an increasing root, then the value of M is

2X / (x-1) + (3-m) / (2-x) = 0. If both sides of the equation are multiplied by (x-1) (2-x), 2x (2-x) + (3-m) (x-1) = 04x-2x ^ 2 + (3-m) x + M-3 = 02x ^ 2 - (7-m) x + (3-m) = 0 if the augmented root of the equation is x = 1, then 2 - (7-m) + (3-m) = 0, - 2 = 0, so the increasing root of the equation is not x = 1

When m=______ The equation 2x with respect to X x−3=3+m X − 3 produces root augmentation

Multiply both sides of the equation by (x-3)
2x=3（x-3）+m，
∵ the original equation has an increasing root,
The simplest common denominator x-3 = 0, i.e. the augmented root is x = 3,
Substituting x = 3 into the integral equation, M = 6

When m is the value, the equation 3-2x / 2-x + - M / 2X-4 = 1 has an increasing root?

3-2x / 2-x + - M / 2X-4 = 1 with root augmentation
（6-4x+m）/(4-2x)=1;
(6-4x+m-4+2x)/(4-2x)=0;
(m+2-2x)/(4-2x)=0;
Because there are roots;
So the numerator of the solution set is zero;
4-2x=0；
x=2；
m+2-4=0;
m=2;
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On the equation of X 2x / (x + 1) - M / (x ^ 2 + x) = (3x + 1) / x, when m is the value, it will produce the root augmentation

2X / (x + 1) - M / (x ^ 2 + x) = (3x + 1) / X2X ^ 2-m = (3x + 1) (x + 1) 2x ^ 2-m = 3x ^ 2 + 4x + 1x ^ 2 + 4x + 1 + M = 0 solution equation: X (x + 1) = 0 know: possible augmented roots are: 0, - 1 when augmented roots are 0: 0 + 0 + 1 + M = 0, M = - 1: 1-4 + 1 + M = 0, M = 2

It is known that x = 3 is the root of the equation 2x-m minus 1 / 2 equals to x-m of 3. Find the value of M

2x-m minus 1 / 2 = (6-m) / 4-0.5
3 x-m = (2-m) / 3
(2-m)/3=(6-m)/4-0.5
8-4m=18-3m-6
m=-4
The root of the equation is the solution of the equation

When m is the value, the equation 2x / x + 1-m / x? 2 + x = x + 1 / X has an increasing root

M=2
2x/x+1-m/x²+x=x+1/x
2x²+x²-m+x3=x3+x
3x²-m-x=0
Using cross multiplication, we can get that when m = 2 is, there is a true root

Given that x = 1 / 2 is the root of the equation (2x-m) / 4-1 / 2 = (x-m) / 3, find the value of the algebraic expression 1 / 4 (- 4mm + 2m-8) - (1 / 2 m-1)

(2x-m)/4-1/2=(x-m)/3
X = 1 / 2
(1-m)/4-1/2=(1/2-m)/3
M=5
1/4(-4mm+2m-8)-(1/2 m-1)
=1/4(-100+10-8)-(1/2*5-1)
=-49/2-3/2
=-26

If x = - 2 is a solution of the equation 2x + M = 4, then the value of M is () A. 8 B. -8 C. 2 D. 0

By substituting x = - 2 into the equation: - 4 + M = 4,
The solution is: M = 8,
Therefore, a

Given that x = - 2 is the root of equation 2x + M-4 = 0, what is the value of M?

Put - 2 in
-4+M-4=0
M=8