The system of three variable linear equations: z = x + y, 2x-3y + 2Z = 5, x + 2y-z = 3 It's better before 10:40

z=x+y.(1)
2x-3y+2z=5.(2)
x+2y-z=3.(3)
Substituting (1) into (2) (3) yields
4x-y=5.(4)
y=3.(5)
Substituting (5) into (4) yields
4x-3=5
X=2
By (1)
z=x+y=5
The solution
X=2
Y=3
Z=5

The equation system of three variables: x + Y-Z = 0 x + 2y-z = 3 2x-3y + 2Z = 5,

x+y-z=0 .1
x+2y-z=3 .2
2x-3y+2z=5.3
2-1
y=3.4
1 * 2 + 3
4x-y=5.5
Substituting 4 into 5
4x-3=5
4x=8
x=2.6
Replace 4 and 5 into 1
2+3-z=0
5-z=0
Z=5
So x = 2, y = 3, z = 5

To solve the system of three variable linear equations 1, x + Y-Z = 4 2x-y + Z = 5, x-3y + Z = - 22, y + 2Z = - 23x + y-4z = 1 2x-y + 2Z = 8 3, x-2y + Z = - 1 x + y + Z = 2 x+2y+3z=-1

1.x+y-z=4 2x-y+z=5 x-3y+z=-2 (x+y-z)+(2x-y+z)=4+5 3x=9 x=3
(2x-y + Z) - (x-3y + Z) = 5 - (- 2) x + 2Y = 7. Substituting x = 3 into x + 2Y = 7, we can get 3 + 2Y = 7, 2Y = 4, y = 2
Substituting x = 3, y = 2 into x + Y-Z = 4 leads to 3 + 2-z = 4 5-Z = 4, z = 1
2. Y + 2Z = - 23x + y-4z = 1 2x-y + 2Z = 8 (y + 2Z = - 2) × 2, 2Y + 4Z = - 4 (3x + y-4z) + (2Y + 4Z) = 1-4
3x + 3Y = - 3 x + y = - 1 (x + y = - 1) × 2, 2x + 2Y = - 2 (2x-y + 2Z) - (y + 2Z) + (2x + 2Y) = 8 - (- 2) - 2
4X = 8 x = 2 (2x-y + 2Z) - (y + 2Z) = 8 - (- 2) 2x-2y = 10 X-Y = 5 substituting x = 2 into X-Y = 5, we can get 2-y = 5, y = - 3
Substituting y = - 3 into y + 2Z = - 2 leads to - 3 + 2Z = - 2 z = 0.5
3. X + y + Z = 1 x + y + Z = 2 x + 2Y + Z = 2 x + 2Y + 3Z = - 1 (x-2y + Z) - (x + y + Z) = - 1-2-3y = - 3 y = 1 (y = 1) put y = 1 into the x-2y + z = - 1, X-2 + Z = - 1 x + Z = 1 (x + 2Y + 3Z) - (x + Z) = - 1-1-1 2y-2z = - 2 Y-Z = - 1 (y = 1) put y = 1 into Y-Z = - 1, get 1-z = - 1, z = 2, y = 1, z = 2, y = 1, z = 2, y = 1, z = 2, y = 1, z = 2, z = 2, z = 2, x + 1 + 2 = 2 x = - 1

Solving the system of three variable linear equations (x-1) / 3 = (Y-3) / 4 = (Z + 2) / 5 2x-3y + 2Z = 1 With addition and subtraction elimination method or substitution elimination method, the answer must be accurate and tested

(x-1) / 3 = (Y-3) / 44x-4 = 3y-93y = 4x + 5Y = (4x + 5) / 3 (x-1) / 3 = (Z + 2) / 55x-5 = 3Z + 6Z = (5x-11) / 3 substituting 2x-3y + 2Z = 12x - (4x + 5) + 2 (5x-11) / 3 = 1-2x-5 + 10x / 3-22 / 3 = 14x / 3 = 40 / 3, so x = 10Y = (4x + 5) / 3 = 15z = (5x-11) / 3 = 13

To solve the system of linear equations, X-Y-Z = 1,2x + y-3z = 4,3x-2y-z = - 1

x-y-z=1（1）,2x+y-3z=4,（2）3x-2y-z=-1（3）
(3) (1) 2x-y = - 2 (4)
(2) - 3 (3) - x + y = 1 (5)
There is (4) (5) x = - 1, substituting (5) for y = 0, and then substituting (1) for Z = - 2

Solving the system of three variable linear equations X: Y: z = 1:2:3,2x-y + 3Z = 21 Solving equations X: Y: z = 1:2:3,2x-y + 3Z = 21 Change it into a system of three variable linear equations: X: y = 1: X: z = 1:3, 2x-y + 3Z = 21

Let x = k, y = 2K, z = 3K
2x-y+3z=21 ===>2k-2k+9k=21
The solution is k = 7 / 3
So x = 7 / 3, y = 14 / 3, z = 7
x:y=1:2,x:z=1:3,2x-y+3z=21
2X = y, z = 3x, substituting 2x-y + 3Z = 21
2x-2x+9x=21
x=7/3
y=14/3
Z=7
In fact, the solution is the same, this is unconventional ternary, my method should be the simplest!

Solving the system of three variable linear equations X: y = 2:1, 2x-y = 3Z, x + y + Z = 20

From X: y = 2:1, x = 2Y, substituting 2x-y = 3Z, we can get x = 2Y
3y=3z,z=y
So x + y + Z = 2Y + y + y = 20, y = 5, x = 10, z = 5
So x = 10, y = 5, z = 5

Solve the following three variable linear equations x = 2Y, 2x-z = 7, y-3z = 10

x=2y(1)
2x-z=7(2)
y-3z=10(3)
Put (1) into (2)
4y-z=7(4)
y-3z=10(3)
(4)*3 12y-3z=21(5)
(5)-(3) 11y=11
Y=1
Substitute y = 1 into (1) x = 2Y = 2 * 1 = 2
Substitute y = 1 into (3) 3Z = Y-10 = 1-10 = - 9
z=-3
x=2,y=1,z=-3

What is the solution of the ternary system of first order equations, X: Y: z = 1:2:3, 2x-y = 3Z = 36

3z=36
z=12
x:y:z=1:2:3
x:y:12=1:2:3
X=4
Y=8
z=12

Solving equations X / 2 = Y / 3 = Z / 5 2x + y + 3Z = 88 help!

If x / 2 = Y / 3 = Z / 5 is multiplied by 15, then 15x / 2 = 5Y = 3Z is obtained
1.2x+6y=88
2.(2x+15x/2)+y=88
It is concluded that 2Y = 3x is substituted into 1
X = 8, y = 12, z = 20

The system of three variable linear equations: z = x + y, 2x-3y + 2Z = 5, x + 2y-z = 3 It's better before 10:40