Solve the equations 2x * + 2XY + 4Y * + x = 19; X * + XY + 2Y * - y = 9

Solve the equations 2x * + 2XY + 4Y * + x = 19; X * + XY + 2Y * - y = 9

x^2+xy+2y^2=9+y
2x^2+2xy+4y^2=18+2y
2x^2+2xy+4y^2+x=19
18+2y+x=19
x+2y=1
x=1-2y
(1-2y)^2+(1-2y)y+2y^2-y=9
4y^2-4y+1+y-2y^2+2y^2-y-9=0
4y^2-4y-8=0
y^2-y-2=0
(y-2)(y+1)=0
y1=2 y2=-1
x1=-3 x2=3

1 / 2x + 3Y = - 6 1 / 2x + y = 3

1/2x+3y＝-6
1/2x+y＝3
3y-y=-6-3
y=-4.5
x=(3-y)/1/2(
x=[3-(-4.5)]*2
x=15

2X + 3Y = 6 3x-2y = - 2 use the addition and subtraction method to solve the bivariate linear equation Let's find y first

2x+3y=6 (1)
3x-2y=-2 （2）
(1) X 3 gives 6x + 9y = 18 (3)
(2) X 2 gives 6x-4y = - 4 (4)
(3) (4) 13y = 22
y=22/13
Substituting (1) gives 2x + 66 / 13 = 6
x=6/13

3x-2y = 6 2x + 3Y = 17 solution of bivariate first order equation by addition and subtraction Writing process and results are urgent

The equation 3y-6y = 6y-6y is obtained
2X + 3Y = 17, multiply 3 to get 6x + 9y = 51
6x+9y-(6x-4y)=51-12
13y=39
Y=3
3x=6+2y
x=12

X / 2 + Y / 3 = 5,2x-3y = - 6

x=6,y=6

Using the addition and subtraction method to solve the binary system of first order equations 2x + 3Y = 63x-2y = - 2

2x+3y=6
3x-2y=-2
4x+6y=12
9x-6y=-6
13x=6
x=6/13
12/13+3y=6
3y=66/13
y=22/13

1、 1. In the bivariate equation 2x-3y = 10, when x = 2, y = (), when y = - 2, x = () 2. In the bivariate equation 1 / 2x-2y = m, when x = 4, y = - 1, M = () 3. Given that a solution of the bivariate equation mx-y = 1 is x = 1, y = 0, then M = () 4. Given that x + 2Y = 2, express x as () by algebraic expression containing y

-2,2
Four
One
x=2-2y

Bivariate equation 2x + y = 5 x-3y = 6

2x+y=5 1)
x-3y=6 2)
1) - 2) × 2
7y=-7
y=-1
Replace with 1)
X=3

X-Y = - 7 {2x-3y = - 10, ｛x－y=－7 2x－3y=－10

x－y=－7①
2x－3y=－10②
①×3-②
3x-2x=-21+10
x=-11
(1) X-11
-11-y=-7
y=-4
That is, the solution of the equations is x = - 11; y = - 4

X-Y = 2Y 0.2x + 3Y = 1?

X-Y = 2Y, then x = 3Y, change X in 0.2x + 3Y = 1 to 3Y