2X + y = 4 x + 3Z = 1 x + y + Z = 7 thank you! Don't jump. I'm a bit slow~

2X + y = 4 x + 3Z = 1 x + y + Z = 7 thank you! Don't jump. I'm a bit slow~

x+3z=1
x=1-3z
2X + y = 4 x + y + Z = 7
2x-x-z=4-7
x-z=-3
1-3z-z=-3
4z=1+3
Z=1
x=1-3=-2
y=7-x-z=7+2-1=8

How to solve the ternary system of first order equations: z = x + y (1) 3x-2y-2z = - 5 (2) 2x + Y-Z = 3 (3)

Oh, MAIGA. Faint

Ternary system of first order equations: 2x + Y-Z = 5 - (1) X-Y + 2Z = - 1 - (2) x + 2Y + Z = - 2 - (3)

(1) + (3): 3x + 3Y = 3, that is, x + y = 1 - (4)
2*（1）+（2）： 5X+Y=9---(5)
(5) - (4): 4x = 8, that is, x = 2
Thus, y = - 1
Z=-2

Ternary system of first order equations x + 2Y = 5 y + 2Z = 8 Z + 2x = 5

XYZ is equal to 123

Solve the following ternary system of linear equations （1） x-4y+z=-3 2x+y-z=18 x-y-z=7 ；(2) 4x+3y+2z=7 6x-4y-z=6 2x-y+z=1

(1) X-4y + Z = - 3 ① 2x + Y-Z = 18, ② X-Y-Z = 7, ③, ① + ②, 3x-3y = 15, that is, X-Y = 5, ④, ② - ③, x + 2Y = 11, ⑤, ⑤ - ④, 3Y = 6, ﹤ y = 2, y = 2, y = 2, x = 7

Solving the system of three variable linear equations 2x + y = 3,3x-z = 7, X-Y + Z = 0

From the first two formulas, we get y = 3-2x, z = 3x-7
X-3 + 2x + 3x-7 = 0, so x = 5 / 3, y = - 1 / 3, z = - 2

To solve the following three variable linear equations: (1) x-z = 4, x + Y-Z = - 1,2y-z = 1 (2) 3x + 4Z = 7,2x + 3Y + Z = 9, X-Y + Z = 8

（1）x-z=4,①
x+y-z=-1,②
2y-z=1 ③
② - 1
Y = - 5 into 3:
-10-z=1
-z=11
Z = - 11
x+11=4
x=-7
So, x = - 7, y = - 5, z = - 11

Solving the system of three variable linear equations 2x + y + Z = 2,2x-y + 2Z = - 1,2x + 2y-z = 2

2x+y+z=2…… （1）2x-y+2z=-1…… （2）2x+2y-z=2…… (3) (1) + (3) is: 4x + 3Y = 4 (4) (3) × 2: 4x + 4y-2z = 4 (5) (2) + (5) is: 6x + 3Y = 3 (6) (4) - (6) obtained: - 2x = 1, x = - 1 / 2  y = [4-4 × (- 1 / 2)] / 3 = 2 ﹥ z = 2

Solve the following equations X / 2-y / 3 = 3,2x-y-9 = y + 5 / 2

3X - 2Y = 18 1
2X - 2Y =9+5/2 2
1 minus 2, x = 13 / 2, y = 3 / 4

Solving equations 2x + y (y-2x) = 9 (x + y) (x + Y-3) = 10 Ten thousand urgent! Solve!

Let x + y = a, then we can get (a-5) (a + 2) = 0 by a (A-3) = 10, and then we can get a = 5 or a = - 2. Then we can put them into the previous equation in two cases, and then we can find out how much X and y are
I think my method is the best solution