4X + 3Y = 10 and 2x-y = 10 fast

4X + 3Y = 10 and 2x-y = 10 fast

x=4 y= - 2

Solving equations: 2x + y = 5 and 4x + 3Y = 7 fast

If 4x + 2Y = 10 (1) 4x + 3Y = 7 (2) (1) - (2), y = - 3x = 4

Solving equations 4x + 3Y = 6 2x-y = 4 4x+3y=6 A kind of 2x-y=4

4x+3y=6 ①
2x-y=4 ②
From ②, y = 2X-4 ③
Take ③ into ① to get 4x + 3 (2X-4) = 6
x=1.8
Replace with ③ y = - 0.4
So x = 1.8, y = - 0.4

If | x + 3y-5 | and (3x-y-1) 2 are opposite numbers to each other, then 2x + y=______ .

According to the meaning of the title,
x+3y−5＝0①
3x−y−1＝0② ，
① + 2, 4x + 2y-6 = 0,
The solution is 2x + y = 3
So the answer is: 3

If the squares of | x-3y-1 | and (2x-y-17) are opposite to each other, then x=___ ,y=___ .

If the squares of | x-3y-1 | and (2x-y-17) are opposite to each other, then x=_ 10__ ,y=__ 3_.
Because they are opposite numbers
 x-3y-1 = 0 and 2x-y-17 = 0
By solving the equations, x = 10, y = 3

It is known that (x + Y-5) 2 and y-2x + 10 | are opposite numbers to each other. Find the values of X and y

∵ (x + Y-5) 2 and | 3y-2x + 10 | are opposite numbers to each other,
∴（x+y-5）2+|3y-2x+10|=0，
Qi
x+y−5＝0①
3y−2x+10＝0② ，
From ①, y = 5-x ③,
③ 3 (5-x) - 2x + 10 = 0,
The solution is x = 5,
By substituting x = 5 into ③, y = 5-5 = 0,
So, the solution of the equations is
x＝5
y＝0 ．

Firstly, it is simplified and then evaluated: (2x-3y) (- 2x-3y) - (- 2x-3y) 2, where x and y satisfy | x + 1 | and (1-y) 2 are opposite numbers to each other

∵ x + 1 | and (1-y) 2 are opposite numbers to each other,
∴|x+1|+（1-y）2=0
∴x+1=0，1-y=0，
∴x=-1，y=1，
The original formula = (- 3Y + 2x) (- 3y-2x) - (2x + 3Y) 2
=9y2-4x2-（4x2+12xy+9y2）
=9y2-4x2-4x2-12xy-9y2
=-8x2-12xy，
When x = - 1, y = 1, the original formula = 4

If the square of (a + 3) and | B-1 | are opposite numbers to each other, and the solution of equation (a + x) / 4-3y = 1 / 2x + B for X is x = - 1, find the value of square + 2 of Y Speed plus points to find the speed to find the correct standard formula

From the question, a + 3 = 0, B-1 = 0
a= -3 b=1
hold
A = - 3 B = 1 x = - 1 into the equation (a + x) / 4-3y = 1 / 2x + B
【（-3+（-1）】/4-3y=1/2×（-1）+1
-1-3y= 1/2
3y= -3/2
y= -1/2
y²+2
=（-1/2）²+2
=9/4

If the square of (a + 3) and the absolute value of B-1 are opposite to each other, and the solution of the equation a + X / 4-3y = 1 / 2x + B is x = - 1, find the value of 2 times the square - 8 of Y And the equation (a + x) / 4-3y = 1 / 2x + B for X

First of all, we can find a and B. because the square of (a + 3) and the absolute value of B-1 are non negative numbers, but they are opposite numbers, so a + 3 = 0, B-1 = 0, a = - 3, B = 1
Then substituting AB x into the equation, y (- 3-1) / 4-3y = - 1 / 2 + 1 is obtained
Y = - 1 / 2 then 2 * (- 1 / 2) ^ 2-8 = - 7.5

Given the square of equation (2x + 3Y) + 3 (2x + 3Y) - 4 = 0, what is the value of 2x + 3Y?

Given the square of equation (2x + 3Y) + 3 (2x + 3Y) - 4 = 0, what is the value of 2x + 3Y?
Let 2x + 3Y = Z, and the original formula can be changed to Z ^ 2 + 3z-4 = 0, that is: (Z + 4) (Z-1) = 0, then z = - 4, or Z = 1
So the value of 2x + 3Y is - 4 or 1