Absolute value x + 3 = - (2x + y) squared 3 / 4x - 3Y + 1 / 4x squared + y

Absolute value x + 3 = - (2x + y) squared 3 / 4x - 3Y + 1 / 4x squared + y

Absolute value x + 3 = (2x + y) squared
The square of the absolute value x + 3 + (2x + y) is 0
x=-3 2x+y=0 y=-2x=6
3/4x^2-3y+1/4x^2+y
=x^2-3y+y
=(-3)^2-3*6+6
=9-18+6
= -3

It is known that the absolute value of 2x + y = 7 is opposite to that of 4x + 3y-7

They are opposite numbers, so
|2x+y-7|+(4x+3y-7)2=0
2x+y-7=0
4x+3y-7=0
X = 7, y = - 7

Given the square + absolute value x + Y-1 = 0 of (2x-3y + 3), and 4x KY = 0, find the value of K

Because (2x-3y + 3) ^ 2 - | x + Y-1 | = 0,
So (2x-3y + 3) ^ 2 = 0, | x + Y-1 | = 0
That is, 2x-3y + 3 = 0 (1), x + Y-1 = 0 (2)
From (1) and (2), x = 0, y = 1
And 4x-ky = 0, i.e. 4 * 0-k = 0, k = 0
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If the absolute value of the square of (2x + 3y-18) + 4x + 5y-32 = 0, then the value of 4x-3y is equal to ()

(2x+3y-18)^2+|4x+5y-32|=0
2x+3y-18=0
4x+5y-32=0
2x+3y=18
4x+5y=32
2x+2y=14
Y=4
X=3
4x-3y=12-12=0

Given that the solutions of the equations {2x + 5Y = - 6, MX NY = - 4} and {3x-5y = 10, NX + my = - 8} have the same solution, find the value of (2m + n) ^ 2011

2X + 5Y = - 63x-5y = 10 add 5x = 4x = 4 / 5Y = -- 38 / 25 into the other two 4m / 5 + 38n / 25 = - 44N / 5-38m / 25 = - 8, i.e. 10m + 19n = - 50 (1) 19m-10n = 100 (2) (1) * 39 + (2) * 28922m + 461n = 8502m + n = 850 / 461, so ((2m + n) ^ 2011 = (850 / 461) ^ 2011 your title is wrong

The solution of the equation system {2x + 5Y = - 6 MX NY = - 4 is the same as that of {3x-5y = 16 NX + my = - 8

∵ the equation system {2x + 5Y = - 6 MX NY = - 4 is the same as {3x-5y = 16 NX + my = - 8
ν 2x + 5Y = - 6 3x-5y = 16, x = 2, y = - 2
The result is 2m + 2n = - 42n-2m = - 8, and the solution is m = 1, n = - 3
The 2009 power of (2m + n) = (2 × 1-3) = - 1

Given that the solutions of the equations 2x-5y = - 26, MX NY = - 4 are the same as those of the equations 3x-5y = 36, NX + my = - 8, find the value of (M + 2n) ^ 2011

There is one equation in each of the two equations, which is independent of M and n
2x-5y=-26
3x-5y=36
Solve x, y
If we put in another two equations and solve m, N, we can get the value of (M + 2n) ^ 2011

It is known that {x = 1, y = - 2 is the system of equations {3x-4y-m = 0,2x + ny-10 = 0, find the value of M, n

Replace x = 1, y = - 2 into 3x-4y-m = 0,2x + ny-10 = 0
It can be concluded that M = 11, n = - 4

Simultaneous solution of equations by two persons a and B mx+y＝5 2X + NY = 13, a is wrong to read m in ① x＝7 Two Y = - 2, b read the wrong n in ② when solving the problem x＝3 Y = - 7, try to find the solution of the original equations

take
X=7
Two
If y = - 2 is substituted into ②, 2 × 7 is obtained
2 + n × (- 2) = 13, n = - 3,
take
X=3
When y = - 7 is substituted into ①, 3m-7 = 5, M = 4,
The original equations are
4x+y=5
2x-3y=13 ，
① X 3 + 2 gives 14x = 28 and x = 2,
Substituting x = 2 into ① gives y = - 3,
That is, the solution of the original equations is
X=2
y=-3 ．

Simultaneous solution of equations by two persons a and B mx+y＝5 2X + NY = 13, a is wrong to read m in ① x＝7 Two Y = - 2, b read the wrong n in ② when solving the problem x＝3 Y = - 7, try to find the solution of the original equations

take
X=7
Two
If y = - 2 is substituted into ②, 2 × 7 is obtained
2 + n × (- 2) = 13, n = - 3,
take
X=3
When y = - 7 is substituted into ①, 3m-7 = 5, M = 4,
The original equations are
4x+y=5
2x-3y=13 ，
① X 3 + 2 gives 14x = 28 and x = 2,
Substituting x = 2 into ① gives y = - 3,
That is, the solution of the original equations is
X=2
y=-3 ．