2x-y = 4m + 3 x = 2Y + 3 is the solution of the system of equations, and XY is opposite to each other to find the value of M

2x-y = 4m + 3 x = 2Y + 3 is the solution of the system of equations, and XY is opposite to each other to find the value of M

-y=2y+3
3y=-3
y=-1
X=1
arcsinx-x
2+1=4m+3
M=0

Known equations 2x−y＝4m+3 The solution X and y of 2Y − x = − 3 are opposite numbers to each other, and the value of M is calculated

From the meaning of the title
2x−y＝4m+3
2y−x＝−3
x+y＝0 ，
(1) + 2
y＝−1
x＝1 ，
By substituting (1), M = 0

It is known that the solutions of the equations 2x + y = 1 + 3M and X + 2Y = 1-m satisfy the requirements of X + y < 0

2x+y=1+3m ①
x+2y=1-m ②
① + 2 gives 3x + 3Y = 2 + 2m
x+y=(2+2m)/3
∵x+y<0
∴(2+2m)/3<0
2+2m<0
∴m<-1
Or:
2x+y=1+3m ①
x+2y=1-m ②
① + 2 gives 3x + 3Y = 2 + 2m
∵x+y<0
∴3x+3y<0
∴2+2m<0
∴m<-1

Equations 2x+y＝1+3m The solution of X + 2Y = 1 − m satisfies x + y ＜ 0

2x+y＝1+3m①
x+2y＝1−m②
① × 2 is 4x + 2Y = 2 + 6m
③ - 2, 3x = 1 + 7m,
The solution is x = 1 + 7m
3，
Put x = 1 + 7m
2 y = 1-m-1 + 7m
3，
The solution 2Y = 3 − 3M − 1 − 7m
3，
y=1−5m
3，
∵x+y＜0，
∴1+7m
3+1−5m
3＜0，
2+2m
3＜0，
∴2+2m＜0，
∴m＜-1．

On two systems of equations of X, Y: 2 (M + n) X-my = 9, x + y = 5 and MX + NY = 13,2x-y = 4 have the same solution. Find the value of M, n 2 (M + n) X-my = 9, x + y = 5 is a system of equations MX + NY = 13,2x-y = 4 is also a system of equations

First solve x + y = 5
2x-y=4
Add up
3x=9
X=3
y=5-x=2
Put in the other two
6(m+n)-2m=9
4m+6n=9 (1)
3m+2n=13 (2)
(2)×3-(1)
5m=30
M=6
n=(13-3m)/2=-5/2

Given that x = 2, y = 1 is the solution of the system of bivariate linear equations MX + NY = 8 NX my = 1, then the arithmetic square root of 2m-n is urgent

Substitution
2m+n=8
2n-m=1
So m = 2N-1
Then 4n-2 + n = 8
N=2
M=3
2m-n=4
So the arithmetic square root of 2m-n is 2

If 1 + 2 + 3 + +N = a, find the algebraic expression (xny) (xn-1y2) (xn-2y3) (x2yn-1) (xyn)

The original formula = xny · xn-1y2 · xn-2y3 x2yn-1•xyn
=（xn•xn-1•xn-2… x2•x）•（y•y2•y3… yn-1•yn）
=xaya．

If 1 + 2 + 3 + +N = a, find the algebraic expression (xny) (xn-1y2) (xn-2y3) (x2yn-1) (xyn)

The original formula = xny · xn-1y2 · xn-2y3 x2yn-1•xyn
=（xn•xn-1•xn-2… x2•x）•（y•y2•y3… yn-1•yn）
=xaya．

Given that x = 2, y = - 1 is the solution of the system of equations 4mx-x + y = 13,2x NY + 1 = 2, find the value of 2m + 3N

Take the values of X and y to get:
8m-2-1=13 m=2
4+n+1=2 n=-3
2m+3n=2*2+3*（-3）=-5

Given that x, y satisfy the equation system x square + 2Y = 5, X-Y = - 1, find the third power of the algebraic expression x + y fraction X - XY power △ x part x-2x

It is known that x, y satisfy the equation system x power + 2Y = 5, (1) X-Y = - 1 (2) (1) + (2) * 2x 2 + 2x-3 = 0, the solution is X1 = 1 x2 = - 3, substituting (2) Y1 = 2, y2 = - 21. X1 = 1 Y1 = 2, Y1 = 2, x + y is the third power of X + y parts △ x is the x-2x = 1 / (1 + 2) - 1 * 2 ^ (1-2 * 1) / 1 = 1 / 3 + 4 = 4 and 1 / 32. X2 = - 3, y2 = - 2