Given the binary system of first order equations 2x + 3Y = 6,3x-2y = - 2, find x =?, y = ASD

Given the binary system of first order equations 2x + 3Y = 6,3x-2y = - 2, find x =?, y = ASD

2x+3y=6,
3x-2y=-2
Multiply the first by 2,4x + 6y = 12
The second is - 6y
13 / y = 13 x = 6

If the solution of the system of equations: X-Y = 9a, 4x-2y = 32A is also the solution of the bivariate linear equation 2x + 3Y = 8, a =?

From X-Y = 9a and 4x-2y = 32a, x = 7a, y = - 2A
Substituting X and Y into 2x + 3Y = 8, a = 1

On the binary system of first order equations of X and y, the solutions of 2x + 3Y = K-3 and x-2y = 2K + 1 are opposite to each other, and the solution of K is obtained On the system of bivariate linear equations of X and Y {2x+3y=k-3 {x-2y=2k+1 The solution of K is opposite to each other

Let the solution be a, - A
be
2a-3a=k-3,-a=k-3
a-2*(-a)=2k+1,3a=2k+1
By solving the equations, the following results are obtained
k=8/5,a=7/5
k=8/5

Bivariate equation 2x + 3Y = 6 3x-2y = - 2

2X+3Y=6 ①
3X-2Y=-2②
① * 3 - ② * 2
13Y=22
Y=22/13
Put in
X=6/13

X + 3Y = 4,2x-3y = - 1, what is the solution of this bivariate equation

x + 3y = 4 ①
2x - 3y = -1 ②
① + 2
3x = 3
x = 1
Substituting x = 1 into x + 3Y = 4 gives:
y = 1
To sum up:
x = 1
y = 1

X + 1 = 5 (y + 2), 3 (2x-5) - 4 (3Y + 4) = 5 to solve bivariate linear equation

From equation 1, x = 5Y + 9, and substituting it into equation 2
3(2(5y+9)-5)-4(3y+4)=3(10y+13)-4(3y+4)=18y+23=5
So y = - 1
So x = 4

The solution of bivariate equation x-3y = 2,2x + y = 18

X-3y = 2 (1) 2x + y = 18 (2) (1) + (2) × 3, 7x = 56 solution, x = 8, substituting x = 8 into (2), 2 × 8 + y = 18, the solution of original equation system is: x = 8y = 2

To solve the system of bivariate linear equations x＝3y−5 3y＝8−2x ．

x＝3y−5 ①
3y＝8−2x ②
By substituting ① into ②, we get 3Y = 8-2 (3y-5) and y = 2 (3 points)
By substituting y = 2 into ①, we can get: x = 3 × 2-5 (4 points), and x = 1 (15 points)
So the solution of this system of quadratic equations is
x＝1
(y = 6)
So the answer is:
x＝1
y＝2 ．

Solving bivariate equation 2x-6y = 1, x = - 3Y + 5

2x-6y=1 1
x=-3y+5 2
Replace formula 2 with formula 1
2(-3y+5)-6y=1
-12y+10=1
12y=9
y=3/4
x=-3*3/4+5=11/4

2x−3y＝7① x−3y＝7② ．

① - 2: x = 0,
Substituting x = 0 into ②, 0-3y = 7,
The solution is: y = - 7
3．
Then the solution of the equations is
x＝0
y＝−7
3 ．