The solution of this equation, y + 3, x = 2, x = 2

The solution of this equation, y + 3, x = 2, x = 2

Let X / 2 = Y / 3 = Z / 5 = k, then: x = 2K, y = 3k, z = 5K
Substituting into the equation 2x + y + 3Z = 88, we get: 4K + 3K + 15K = 88, that is: 22K = 88, the solution is: k = 4
So: x = 8, y = 12, z = 20

The solution of the system of three variable linear equations: x-z = - 1,2x + y + 3Z = 5, x + Y-Z = 1

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To solve the system of bivariate linear equations. Title: 2x + 3Y = 4, x + 1 / 2Y = 0, 2x = 5 [x + y], 3x-10 [x + y] = 2

X + 1 / 2Y = 0 both sides are multiplied by 2 to get 2x + y = 0. Subtracting the two formulas yields 2Y = 4, y = 2x = - 1
2X = 5 [x + y], move the right to the left, multiply two by two to get 2x-10 [x + y] = 0, and subtract the two formulas to get x = - 2, y = 6

[(3x+y)(x-y)-(2x+3y)(x-y)]*(x-y)

=(x-y)[(3x+y)-(2x+3y)]*(x-y)
=(x-y)*(x-y)(3x+y-2x-3y)
=(x-y)(x-y)(x-2y)
Is it simplification, or is it?
=(x*x-2xy+y*y)(x-2y)
=x^3-4x*x*y+5xy*y-2y^3

If x ^ 3 + y ^ 2-5 = 7, then 2x ^ 3 + 2Y ^ 2 + 4 =?

Because x 3 + y 2 - 5 = 7
So x 3 + y 2 = 12
So 2x? + 2Y? = 24
So 2x ^ 3 + 2Y ^ 2 + 4 = 28

4 times x = 5 parts y, 2x-3y = - 7, to solve, we need to process, Thank you

4 times x = 5 parts y
5x-4y=0………… (1)
2x-3y=-7………… II.
① × 3 - ② × 4
7x=28
X=4
If x = 4 is taken into ①, the
20-4y=0
Y=5
∴x=4,y=5

It is known that 2x-5y + 7 = 0, if x = 5, y =, if y = - 4, X=

Substituting x = 5 into 10-5y 7 = 0, then y = 5 / 17; substituting y = - 4 into 2x 207 = 0, then x = - 2 / 27

Given y = (x + 1) ^ 7 (2x + 3) ^ 4 (2x-1) ^ 5, find dy / DX Please, everyone

Y derivation = 7 (x + 1) ^ 6 (2x + 3) ^ 4 (2x-1) ^ 5 + (x + 1) ^ 7 * 4 (2x + 3) ^ 3 * 2 * (2x-1) ^ 5 + (x + 1) ^ 7 (2x + 3) ^ 4 * 5 (2x-1) ^ 4 * 2
=7(x+1)^6(2x+3)^4(2x-1)^5+8(x+1)^7*(2x+3)^3*(2x-1)^5+10(x+1)^7(2x+3)^4*(2x-1)^4

To solve the equations: (1) x / 4 + Y / 3 = 7 x / 3 + Y / 2 = 8 (2) 2x-1 / 3 = y + 3 / 2-22 2 (x-3) - (Y-2) = 5

1、3x+4y=84 2x+3y=48
The solution is: x = 60, y = - 24
2、12x-2=6y+9-6 4x-6-y+2=5
The solution x = 49 / 12 y = 22 / 3 doubts whether the first formula of this problem is (2x-1) / 3 = (y + 3) / 2-2

The system of equations 2x-y + Z = 3 5x + 2Y + Z = 7 x + Y-Z = 5 x =? Y =? Z =?

x = 8/3,
y = -4/3,
z = -11/3