If we know that the equation x + X is a root______ .

If we know that the equation x + X is a root______ .

According to the meaning of the title, we can get
2×（-2）2-2m-4=0，
M = 2
So the answer is: 2

It is known that the solution of inequality group ① 2x-a < 1 ② x-2b > 3 is - 1 Math homework help users 2017-10-16 report Use this app to check the operation efficiently and accurately!

By solving these two inequalities respectively, the following results are obtained
2x-a2b+3,
The solution set of the original inequality system is: 2B + 3

It is known that the solution set of the inequality system x-a is greater than or equal to B 2x-3 and less than 2B + 1 is - 3 less than or equal to x less than 5, then the value of B in a is

x-a>=b x>=a+b
2x-3

If {3x-a is greater than or equal to 0, the integer solution of 2x-b is less than or equal to 0, only 1,2 is obtained, So how many ordinal pairs (a, b) of integers a and B are suitable for this inequality?

3x-a≥0①
2x-b≤0②
From ①, X ≥ A / 3
From (2): X ≤ B / 2
The solution set of inequality system is a / 3 ≤ x ≤ B / 2
∵ the integer solution is only 1,2
/ / 0 < A / 3 ≤ 1,2 ≤ B / 2 < 3 (you should be able to understand this step by analyzing on the number axis)
The solution is: 0 < a ≤ 3,4 ≤ B < 6
∴a=1,2,3
b=4,5
The ordinal number pairs (a, b) composed of integers a and B are 3 × 2 = 6
Therefore, there are six ordinal pairs (a, b) composed of integers a and B

If 2x-a of inequality system is large equal to 0, and the integer solution of 3x-b less than 0 is only 1.2.3, then how many integers a and B are suitable for this inequality group

2x-a ≥ 0 leads to X ≥ 0.5A, and 3x-b ＜ 0 leads to x 〈 B / 3. Because only 1,2,3 are integer solutions, then 0 〈 0.5A ≤ 1,3 〈 B / 3 ≤ 4 is obtained. Therefore, 0 〈 a ≤ 2,9 〈 B ≤ 12 is obtained. Because X and y are integers, then x = 1 or 2, y = 10 or 11 or 12

Find the integral solution of the inequality group 3x + 1 greater than or equal to 2x, X / 2 greater than - 4, 3x + 1 less than 10

3x + 1 ≥ 2x, X ≥ - 1
X / 2 > - 4, x > - 8
3x+1

Solving inequality group 2x - (2x-1) / 2

①2x-（2x-1）／2＜1 ②（3x-4）／x≤2x+3
①∶4x-2x+1＜2 ,x＜1/2
②∶3x-4≤2x²+3x ,2x²≥-4 ,x²≥-2 ,∵x²≥0 ,∴x≥0,
∵x＜1/2 ,∴x=0

The inequality group 2x + 5 is greater than 1 and 3x-8 is less than or equal to 10

If 2x + 5 ＞ 1, then x ＞ - 2
If 3x-8 ≤ 10, then x ≤ 6
Therefore, the solution set of inequality system is - 2 < x ≤ 6
Because: the solution of X is an integer
So: the integer solution is: - 1,0,1,2,3,4,5,6

Solving inequality system x-3 (X-2) is greater than or equal to 4, 1 + 2x / 3 is greater than X-1

One
X-3 (X-2) greater than or equal to 4
3-3x + 6 is greater than or equal to 4 - 2x is greater than or equal to - 2, and X of - 2 is less than or equal to 1
1 + 2x / 3 is greater than X-1
3 + 2x of 3 on both sides is greater than 3x-3
X is less than 6

Solving inequality system: x + 1 / 2-2x-1 / 10 > 4x + 3 2x + 1 / 3-1 is greater than or equal to X-1 / 2

The original formula = [1 / (x + 1)] - [(x + 3) / (x? - 1)] × [(x? - 2x + 1) / (x? + 4x + 3)]
=[1/(x+1)]-{ (x+3)/[(x+1)(x-1)] }×{ (x-1)²/[(x+1)(x+3)] }
=[1/(x+1)]-[(x-1)/(x+1)²]
=[(x+1)/(x+1)²]-[(x-1)/(x+1)²]
=[(x+1)-(x-1)]/(x+1)²
=(x+1-x+1)/(x+1)²
=2/(x+1)²