One root of the equation x / 1-x = 2x / 1-ax is x = - 1 / 2. Find the value of A

One root of the equation x / 1-x = 2x / 1-ax is x = - 1 / 2. Find the value of A

Substituting x = - 1 / 2 into - 1 / 2 / (1 + 1 / 2) = - 1 / 2 * 2 / (1 + A / 2)
That is, 1 + A / 2 = 3
A=4

It is known that the minimum integer solution of inequality 5 (X-2) + 8 < 6 (x-1) + 7 is the solution of equation 2x AX = 3, and polynomial 4a-14 is obtained /The value of A

5x-10+8<6x-6+7
5x-2<6x+1
x>-3
So the solution is x = - 2
-4+2a=3
a=7/2
So 4a-14 = 14-14 = 0

Equation ax-6 = 2x, can you find out the relationship between the solution X of the equation and the value of a? When a goes to what kind of integer, the solution of the equation is positive integer, and find these positive integer solutions

A = 2, no solution
A is not equal to 2, x = 6 / (A-2)
6=1*6=2*3
X is a positive integer
a-2=1,a=3,x=6
a-2=6,a=8,x=1
a-2=2,a=4,x=3
a-2=3,a=5,x=2

The minimum integer solution of 6 (x-1) + 7 > 5 (X-2) + 8 is the solution of the equation 2x AX = 3. Find the value of A

Solving inequality: 6x-6 + 7 > 5x-10 + 8
x>-3
Its minimum integer solution is x = - 2
Substituting it into the equation, 2 * (- 2) - A * (- 2) = 3
-4+2a=3
a=3.5

Solve the equation ax-6 = 2x with respect to x, and find the positive integer solution of the equation when a is an integer

Because x + X can't be x + 0 because it's not about X
So a = 2x + 6 / X
a=2+6/x
When a is an integer, A-2 is also an integer, so 6 / X is an integer
So x can only be a number divisible by 6, that is, prime number of 6
So the solution is 1 2 3 6
That is, x = 1 2 3 6

If the equation 2x / x-3-m = m / x-3 for X has no solution, then the value of M is

Multiply x-3 on both sides
2x-mx+3m=m
(m-2)x=2m
When m = 2, the equation has no solution
If M ≠ 0
Then x = 2m / (m-2)
If there is no solution, the root is added
The denominator is 0
So 2m / (m-2) = 3
2m=3m-6
M=6
therefore
m=2,m=6

On the equation 2x of X x−2+3−m If 2 − x = 3 has an increasing root, then the value of M is______ .

Multiply both sides of the equation by (X-2)
2x-（3-m）=3（x-2），
∵ the original equation has an increasing root,
The simplest common denominator X-2 = 0, i.e. the augmented root is x = 2,
Substituting x = 2 into the integral equation, M = - 1

If the equation 2x about X x−4＝|m−2| If x − 4 has no solution, then the value of M is______ .

According to the meaning of the title, x-4 = 0, that is, x = 4
Substituting x = 4 into 2x = m-2 or 2x = - (m-2), M = 10 or - 6 can be obtained

If the equation x + 1 / m-2x + 3 / 2 = - 1 has no solution, then M is Hurry up,

X + 1 / 2 m-2x + 2 / 3 = 2x + 2m-3 = - 1, so 2m-3 = 0, so m = 3 / 2

On the equation X3 of X 3-2x-3-x-2 + MX = - 1 no solution to find the value of M

(3-2x)/(x-3)-(2+mx)/(3-x)=-1
Multiply x-3 to get 3-2x + (2 + MX) = - x + 3
The solution is: x = - 2 / (m-1)
There is no solution to the equation, and ν x = - 2 / (m-1) is an augmented root x = 3
Namely: - 2 / (m-1) = 3
The solution is: M = 1 / 3