三元一次方程組:z=x+y,2x-3y+2z=5,x+2y-z=3 最好在10:40分前.

三元一次方程組:z=x+y,2x-3y+2z=5,x+2y-z=3 最好在10:40分前.

z=x+y.(1)
2x-3y+2z=5.(2)
x+2y-z=3.(3)
把(1)代入(2)(3)得
4x-y=5.(4)
y=3.(5)
把(5)代入(4)得
4x-3=5
x=2
由(1)
z=x+y=5
解得
x=2
y=3
z=5

三元一次方程組:x+y-z=0 x+2y-z=3 2x-3y+2z=5解出來,

x+y-z=0 .1
x+2y-z=3 .2
2x-3y+2z=5.3
2式-1式得
y=3.4
1式*2+3式得
4x-y=5.5
將4式代入5式得
4x-3=5
4x=8
x=2.6
將4式,5式代入1式得
2+3-z=0
5-z=0
z=5
所以x=2,y=3,z=5

解三元一次方程組1、x+y-z=4 2x-y+z=5 x-3y+z=-2 2、y+2z=-2 3x+y-4z=1 2x-y+2z=8 3、x-2y+z=-1 x+y+z=2 x+2y+3z=-1

1.x+y-z=4 2x-y+z=5 x-3y+z=-2(x+y-z)+(2x-y+z)=4+5 3x=9 x=3
(2x-y+z)-(x-3y+z)=5-(-2)x+2y=7把x=3代入x+2y=7可得3+2y=7 2y=4 y=2
把x=3,y=2代入x+y-z=4可得3+2-z=4 5-z=4 z=1
2.y+2z=-2 3x+y-4z=1 2x-y+2z=8(y+2z=-2)×2可得2y+4z=-4(3x+y-4z)+(2y+4z)=1-4
3x+3y=-3 x+y=-1(x+y=-1)×2可得2x+2y=-2(2x-y+2z)-(y+2z)+(2x+2y)=8-(-2)-2
4x=8 x=2(2x-y+2z)-(y+2z)=8-(-2)2x-2y=10 x-y=5把x=2代入x-y=5可得2-y=5 y=-3
把y=-3代入y+2z=-2可得-3+2z=-2 z=0.5
3、x-2y+z=-1 x+y+z=2 x+2y+3z=-1(x-2y+z)-(x+y+z)=-1-2 -3y=-3 y=1把y=1代入x-2y+z=-1可得x-2+z=-1 x+z=1(x+2y+3z)-(x+z)=-1-1 2y-2z=-2 y-z=-1把y=1代入y-z=-1可得1-z=-1 z=2把y=1,z=2代入x+y+z=2可得x+1+2=2 x=-1

解三元一次方程組(x-1)/3=(y-3)/4=(z+2)/5 2x-3y+2z=1 用加减消元法或者代入消元法,答案一定要準確,檢驗過.(不要設k法)

(x-1)/3=(y-3)/44x-4=3y-93y=4x+5y=(4x+5)/3(x-1)/3=(z+2)/55x-5=3z+6z=(5x-11)/3代入2x-3y+2z=12x-(4x+5)+2(5x-11)/3=1-2x-5+10x/3-22/3=14x/3=40/3所以x=10y=(4x+5)/3=15z=(5x-11)/3=13

解三元一次方程組,x-y-z=1,2x+y-3z=4,3x-2y-z=-1

x-y-z=1(1),2x+y-3z=4,(2)3x-2y-z=-1(3)
(3)-(1)得2x-y=-2(4)
(2)-3(3)得:-x+y=1(5)
有(4)(5)得x=-1,代入(5)得y=0,再代入(1)得z=-2

解三元一次方程組x:y:z=1:2:3,2x-y+3z=21 解方程組x:y:z=1:2:3,2x-y+3z=21 換成三元一次方程組:x:y=1:x:z=1:3,2x-y+3z=21

設x=k,y=2k,z=3k
2x-y+3z=21 ===>2k-2k+9k=21
解得k=7/3
所以x=7/3,y=14/3,z=7
x:y=1:2,x:z=1:3,2x-y+3z=21
2x=y,z=3x,代入2x-y+3z=21
2x-2x+9x=21
x=7/3
y=14/3
z=7
其實解法一樣的這是非常規三元一次我的方法應該最簡單了!

解三元一次方程組x:y=2:1,2x-y=3z,x+y+z=20

由x:y=2:1得x=2y,代入2x-y=3z,可得
3y=3z,z=y
於是x+y+z=2y+y+y=20,y=5,x=10,z=5
於是x=10,y=5,z=5

解下列三元一次方程組x=2y,2x-z=7,y-3z=10

x=2y(1)
2x-z=7(2)
y-3z=10(3)
把(1)代入(2)
4y-z=7(4)
y-3z=10(3)
(4)*3 12y-3z=21(5)
(5)-(3)11y=11
y=1
把y=1代入(1)x=2y=2*1=2
把y=1代入(3)3z=y-10=1-10=-9
z=-3
x=2,y=1,z=-3

三元一次方程組,x:y:z=1:2:3 2x-y=3z=36的解是多少

3z=36
z=12
x:y:z=1:2:3
x:y:12=1:2:3
x=4
y=8
z=12

解方程組x/2=y/3=z/5 2x+y+3z=88 救命!

由x/2=y/3=z/5都乘以15得出15x/2=5y=3z則有
1.2x+6y=88
2.(2x+15x/2)+y=88
得出:2y=3x代入1
得出:X=8 Y=12 Z=20