The image vertex coordinates () of quadratic function y = - 2x, when x = (), y has the most () value ()

The image vertex coordinates () of quadratic function y = - 2x, when x = (), y has the most () value ()

When x = 0, y has a maximum value of 0
If 3Y + 7 divided by (Y-1) (Y-2) = a divided by (Y-1) + B divided by (9y-2)
Finding the value of a and B
because
(3y+7)/[(y-1)(y-2)]=A/(y-1)+B/(y-2);
So: (3Y + 7) / [(Y-1) (Y-2)] = [a (Y-2) + B (Y-1)] / [(Y-1) (Y-2)];
So: 3Y + 7 = (a + b) y-2a-b;
Because the coefficient of Y is 3;
The constant without y is 7;
So we can get a + B = 3. (1);
-2A-B=7.(2);
The solution of simultaneous (1) (2) is: a = - 10; b = 13
What is the elliptic standard equation with focus coordinates (- radical 3,0), (radical 3,0) and passing through point (2,1)?
Let the equation be x ^ 2 / A ^ 2 + y ^ 2 / b ^ 2 = 1, because the focal length is double follow sign 3, so C ^ 2 = 3, so C ^ 2 = a ^ 2-B ^ 2 = 3. Then bring the point (follow sign 3, - 1 / 2) into the equation, and get 3 / A ^ 2 + 1 / 4B ^ 2 = 1. Set up the equations, and get a ^ 2 = 4, B ^ 2 = 1, so the elliptic equation is x ^ 2 / 4 + y ^ 2 = 1
If the true value of a number is -0.1010, and the number is expressed as 1.0110 in the computer, then the coding method of the number is
Take negative + 1, for complement!
Solve the equation, the square of 4Y = 3Y, solve the equation, the square of 4Y = 3Y
4y²=3y
4y²-3y=0
y(4y-3)=0
y=0,y=3/4
y1=0 y2=3/16
4y2-3y=0
y(4y-3)=0
Y = 3 or y = 4
4y^2=3y
y(4y-3)=0
Y = 0 or 3 / 4
Square of 4Y = 3Y
4y²-3y=0
y(4y-3)=0
How can there be two
When m = what, the solution of equation 5x-2 = 4x + 1 is the same as that of equation 2 (x-1) + 2m = - (M + 1)
A: the solution of the first equation 5x-2 = 4x + 1 is x = 3, which is also the solution of the second equation. Substituting it into 2 (3-1) + 2m = - (M + 1), the solution is m = - 5 / 3
5x-2=4x+1
5x-4x=2+1
X=3
2(x-1）+2m=-(m+1）
2(3-1)+2m=-m-1
4+2m=-m-1
2m+m=-4-1
3m=-5
m=-5/3
A: when m = - 5 / 3, the solution of equation 5x-2 = 4x + 1 is the same as that of equation 2 (x-1) + 2m = - (M + 1)
If Y > x > 0, X ˇ 2 + 9y ˇ 2-8xy = 0, find the value of (x + 3Y) divided by (x-3y)?
∵ ,x^2+9y^2-8xy=0,∴ (x+3y)^2=14xy,(x-3y)^2=2xy,∴(x+3y)^2/(x-3y)^2=14/2=7,
∵ y＞x＞0,∴x-3y＜0,∴(x+3y)/(x-3y)= -√7 .
Taking the left vertex of the ellipse x square / 64 + y square / 16 = 1 as the focus, and the inclination angle of an asymptote is 5 / 6 π, the hyperbolic equation is solved
c²=64-16=48
Then a & # 178; + B & # 178; = 48
And - B / a = k = - √ 3 / 3
a=√3b
So B & # 178; = 12, a & # 178; = 36
So x & # 178 / 36-y & # 178 / 12 = 1
The machine number 1111o111 is transformed into a true value of? A. - 191 B. - 1110111 why and how
A
Solving the equation 4Y ^ 2 = 3Y
In the evening, the problem is settled
4y²=3y
4y²-3y=0
y(4y-3)=0
Y = 0 or 4y-3 = 0
y1=0,y2=3/4
y1=0
Y2 = 3 / 4
y(4y-3) =0
Y = 0 or y = 3 / 4
Y = 0 or y = 3 / 4