A. The distance between B and B is 360 km. The speed of the truck is 60 km / h from a to B. the speed of the car is 1.5 times that of the truck. The truck starts for 1 hour

A. The distance between B and B is 360 km. The speed of the truck is 60 km / h from a to B. the speed of the car is 1.5 times that of the truck. The truck starts for 1 hour

According to the meaning of the title, cars and trucks travel 360 - 60 * 1 - 150 = 150 km
Formula:
Speed of car: 60 × 1.5 = 90 km
Cars and trucks travel together: 360-60 * 1-150 = 150 km
According to the distance to be traveled by two cars, the speed of two cars and the time to be traveled
150 ／ (60 + 90) = 150 ／ 150 = 1 hour
What do you want to ask?
Are you finished? yes! The following question is: how many hours after the car starts from B to a, is the distance between the two cars 150 km? 60 × 1.5 = 90 km / h, 1 × 60 = 60 km, set up a car to start for X hours, 360-60-60x-90x = 150 - 150x = - 150 x = 1 A: after the car starts for 1 hour
Not finished? Question: Yes! The following question is: how many hours after the car starts from B to a, is the distance between the two cars 150 km?
Solve the equation x ^ 2 + 6x + 2 under the root sign - x ^ 2 + X + 2 = x under the root sign
2 minus 1 / 15 is exactly 70% of a number. What's the number? What's the number more than 12? What's the fraction of 24?
(2-1/15)/70%=58/21 (12+4)/24=2/3
The distance between a and B is 300 km. The passenger cars and freight cars start from a to B at the same time. The speed of freight cars is 60 km per hour, and that of passenger cars is 40 km per hour,
After arriving at the second place, the car immediately returns to the first place at the same speed. A few hours after starting from the first place, the two cars meet?
Meeting time: (300x2) / (60 + 40) = 6 (hours)
Solving equation 6x = 1-radical x
6x=1-√x
6x+√x-1=0
(3√x-1)(2√x+1)=0
√ x = 1 / 3 √ x = 1 / 2 (rounding off)
x=1/9
A number minus 40% is equal to 2.88. What's the number
2.88÷（1-40%）
=2.88÷0.6
=4.8
2.88÷（1-40%）
=2.88÷0.6
=4.8
According to "a number minus its 40% equals 2.88", we can know that 1-40% of this number is 2.88. So this number is 2.88 (1-40%) = 4.8
Let this number be x, then x-40 / 100 = 2.88
The distance between Party A and Party B is 330km. On the map of 1:6000000 scale, how many centimeters is the distance between Party A and Party B on the map?
Set to xcm
x：33000000=1：6000000
x=33/6=11/2=5.5
The distance between a and B on the map is = 33000000cm / 6000000 = 5.5cm
33000000 divided by 6000000 is 5.5cm
It is known that vector a = (4cos α, sin α), vector b = (sin β, 4cos β) and vector C = (COS β, - 4sin β)
(1) If a ⊥ (B-C) finds the absolute value of Tan (α + β) (2) finds the absolute value of (B + C)
If a ⊥ (b-2c) is Tan (α + β)? 1. B-2c = (sin β, 4cos β) - 2 (COS β, - 4sin β) = (sin β - 2cos β, 4cos β + 8sin β). A is perpendicular to b-2c, then 4cosa * (sin β - 2cos β) + Sina * (4cos β + 8sin β) = 0sina * cos β + cosa * sin β - 2 (COSA * cos β - Sina * sin
2 / 3 of a number minus 55 equals 5. What is the number
Ninety
Two thirds of this number is 60, so this number is 90
2/3X-55=5
2/3X=60
X=60x3/2
X=90
The sum of 5 and 55 divided by 2 / 3
This number is:
（5+55）*3/2=90
On the map with a scale of 1:6000000, the distance between a and B is 25cm. A plane flies from a to B at 9:30 a.m. and arrives at 10:45 a.m. how many kilometers does the plane travel per hour?
What is the actual distance between a and B
25 △ 1 / 6000000 = 150000000 cm = 1500km
What's the flight time
10: 45-9:30 = 1:15 = 5 / 4:00
The plane travels every hour
1500 △ 5 / 4 = 1200 km
Actual distance = 25 / (1:6000000) = 150000000cm = 1500km
Time = 10:45-9:30 = 1:15 = 1.25
1500 / 1.25 = 1200 km / h
25*6000000=150000000
150000000/100000=1500
1500/1.25=1200
Brush points
What is the actual distance between a and B
25 △ 1 / 6000000 = 150000000 cm = 1500km
What's the flight time
10: 45-9:30 = 1:15 = 5 / 4:00
The plane travels every hour
1500 △ 5 / 4 = 1200 km