The speed of car a is 80% of that of car B. when car a meets car B, it travels 24 kilometers less than that of car B. when car B meets car a, it travels several thousand meters

The speed of car a is 80% of that of car B. when car a meets car B, it travels 24 kilometers less than that of car B. when car B meets car a, it travels several thousand meters

24÷（1-80%）
=24÷0.2
=120 km
agree with
First, find out how much faster B is than a, and then divide it by 24 km
Formula: 24 △ 1-80% = 24 △ 0.2 = 120 km
A and B start at the same time from AB and run in opposite directions. After 5 hours, they meet. It is known that B has traveled 180 km, and the speed of B and B is high
A and B start at the same time from AB and run in opposite directions. After 5 hours, they meet. It is known that B has traveled 180 km, and the speed ratio of a and B is 5: how many km is the distance between AB and B?
There is another question: once, three friends of a, B and C shared a taxi and agreed to share the fare. A got off at 1 / 3 of the whole journey, and B got off at 2 / 3 of the journey. Finally, C got to the destination by himself and paid 90 yuan in total. Please calculate. How much should a and B pay C?
The second question is wrong. We have learned it
90 × 1 + 2 + 1 / 3 90 × 1 + 2 + 2 / 3
=90 × 1 / 6 = 90 × 2 / 6
=15 yuan = 30 yuan
It's 100 percent right, because I've done it and I'm right
LZ,
When car a runs 40% of the whole journey, it meets car B and continues to move on after meeting. When car a is still 40% of the whole journey from place B, it will continue to move on
At 44%, car B traveled another 75 km. Q: how many kilometers are there between AB and B? What's the speed ratio of car a and B?
The ratio of a and B speed is: 40%: (1-40)% = 2:3
When a line 1-40% - 44% = 16%, B line x% of the whole process
2:3=16%：x%
So: x = 24
Twenty four percent of the second line is 75 kilometers
The whole journey: 75 △ 24% = 312.5km
Answer: A and B are 312.5km apart; the speed ratio of a and B is 2:3
When car a runs 40% of the whole journey, it meets car B. when car B runs 60% of the whole journey, the speed of car B is 1.5 times that of car a, so car B runs 75 km, car a runs 50 km. When car a is 44% of the whole journey from place B, car a is 56% of place a, then car a runs 16%, 50 / 16% = 312.5 km
AB is 312.5km apart, and the speed ratio of a and B is 2:3
When car a runs 40% of the whole journey, it meets car B. when car B runs 60% of the whole journey, the speed of car B is 1.5 times that of car a, so car B runs 75 km, car a runs 50 km. When car a is 44% of the whole journey from place B, car a is 56% of place a, then car a runs 16%, 50 / 16% = 312.5 km
The distance between the two places is 312.5km, and the speed ratio of a and B is 2:3
The speed ratio of a and B vehicles is:
Speed A: speed B = 40%: (1-40%) = 2:3
The distance between the two places is:
75×2/3÷（1-44%-40%）
=50÷16%
=312.5 (km)
It is known that the opposite number of a is 123 and the reciprocal of B is - 212
So a + 3ba − 2B = − 123 + 3 × (− 25) − 123 − 2 × (− 25) = (- 53-65) / (- 53 + 45) = (- 2515 − 1815) / (− 2515 + 1215) = (− 4315) / (− 1315) = 4315 × 1513
The distance between a and B is 150 kilometers. A and B leave from a and B respectively. A is 60 kilometers per hour, B is 60 kilometers per hour
The distance between a and B is 150 kilometers. A and B leave from a and B respectively, with a speed of 60 kilometers per hour and B speed of 40 kilometers per hour. (1) the two vehicles leave in the same direction at the same time, and B is in the front. How many hours after departure does a catch up with B? (2) the two vehicles turn back and leave at the same time, and how many hours do they travel? The distance between the two vehicles is 550 kilometers? (3) the two vehicles run in opposite directions, start at the same time, and continue to move forward after meeting, When car a arrives at land B, how far is car B from land a?
From "classroom experience"
1.150/（60-40）=7.5h
2.（550-150）/（60+40）=4h
3.150/60=2.5h
150-40*2.5=50km
Three large trucks and two small trucks can carry 36 tons of goods at a time, and four small trucks and five large trucks can carry 62 tons of goods at a time
How much is the second power of a freight car with 5 tons,
One large truck can transport x tons at a time, and one small truck can transport y tons at a time;
A:3X+2Y=36
B:5X+4Y=62
Multiply equation a by 2 to get C:
C;6X+4Y=72
By subtracting equation B from equation c, we get the following result:
X=10
Take x = 10 into equation a
30+2Y=36
Y=8;
That 6x + 5Y = 6 * 10 + 5 * 8 = 100 tons
So: 5 small trucks and 6 large trucks can transport 100 tons at a time
A simple method is used to calculate 1... 72 × 80 + 720 × 22
A simple method is used to calculate 1... 72 × 80 + 720 × 22.138 × 23-46 × 19
1=（80+20）×72=7200
2=46×（3×23-19）
=46×（69-19）
=46×50=2300
The distance between a and B is 1800 km. AB vehicles start from both places at the same time. A vehicle travels 60 km per hour, B vehicle travels 40 km per hour
How many hours later, the two cars are 400 kilometers apart, the two answers are urgent now
Arithmetic method: (1800-400) / (60 + 40) = 14 (hours)
Equation method
Setting: after X hours, the distance between the two cars is 400 meters
（60+40）x=1800-400
100x=1400
x=14
14hours
Large trucks transport 5 tons of goods each time, and small trucks transport 3.5 tons each time. How many times do two trucks transport at the same time, large trucks transport 16.5 tons more than small trucks?
To solve the equation, we must have a way of thinking
Each time a large truck transports less each time a small truck transports, it means that a large truck transports more than a small truck. How many times does it take to get 16.5 tons? The equation (5-3.5) x = 16.5 x = 11
Two people count in turn, one, two, three, but not without counting. From the beginning, who counts to 30 will lose
Well, it should be like this! Whoever counts first will win! First of all, the first one counts like this! Just make sure that the last number after each count is 1, 5, 9, 13, 17, 21, 25, 29! That is to say, there is a difference of four numbers! That's OK! You should understand it more easily! Similarly, if you can only count one
The latter number is about the same
The loss of the second number