A and B start from a and B at the same time, and run in opposite directions. After 5 hours, they meet. It is known that B has traveled 180 km, and the speed ratio of a and B is 5:6

A and B start from a and B at the same time, and run in opposite directions. After 5 hours, they meet. It is known that B has traveled 180 km, and the speed ratio of a and B is 5:6

The distance ratio of a and B is also 5:6
So the whole process is: 180 △ 6 × (5 + 6)
=30×11
=330km
180+180*5/6=330km
180÷5=36
Speed of a: 36 △ 6 × 5 = 30
（36+30）×5=330
B v = 180 / 5 = 36 (km / h)
A V / b v = 5 / 6, then a v = 30 (km / h)
A driving distance = 30 * 5 = 150 km
Then AB distance = 180 + 150 = 330km
A: AB is 330km away
The two trains of a and B start from station a and B at the same time. When they meet, car a travels 100 kilometers more than car B. It is known that the speed of car B is 35 times that of car a. the length of the railway between station a and B can be calculated
A: the length of the railway between a and B is 400 km
The two trains run from two places at the same time. Car a runs 70 kilometers per hour, while car B runs 20 kilometers less than car A. when they meet, car a runs 90 kilometers more than car B. how many hours do the two cars meet?
It's because the speed is 20 km slower, so it's 90 km less
So the meeting time: 90 / 20 = 4.5 (hours)
How much is 3 out of 14 times 1.6
 
A and B start from 96 kilometers at the same time. The speed ratio of a and B is 8:7. After 5 minutes and 4 hours, they meet. What is the speed ratio of a and B
What's the speed of a and B
96 △ 4 / 5 = 120 (km)
A: 120 × 8 / (8 + 7) = 64 (km)
B: 120 × 7 / (8 + 7) = 56 (km)
It is known that a certain root of the quadratic equation with one variable x square - 2x-5 / 4 = 0 is also the root of the quadratic equation with one variable x square - (K + 2) x + 9 / 4 = 0. To find the value of K% d% a, please write the process. The more detailed, the better
From x ^ 2-2x-5 / 4 = (X-5 / 2) (x + 1 / 2) = 0, the root of the equation is X1 = - 1 / 2, X2 = 5 / 2. (1) if X1 = - 1 / 2 satisfies x ^ 2 - (K + 2) x + 9 / 4 = 0, substitute it into 1 / 4 + (K + 2) / 2 + 9 / 4 = 0, and get k = - 7; (2) if x = 5 / 2 satisfies x ^ 2 - (K + 2) x + 9 / 4 = 0, substitute it into 25 / 4-5 (K + 2) / 2 + 9 / 4 = 0, and get k = 7 / 5; in conclusion, k = - 7 or K = 7 / 5
A passenger car and a freight car start from a and B at the same time, and travel in opposite directions. The passenger car travels 80 kilometers per hour, and the freight car 65 kilometers per hour. The two cars are just right
How many kilometers is the distance between a and B?
It's more than 45 kilometers,
The distance of the truck is 45 kilometers less than half of the whole journey
So the distance difference is 45 * 2
Time = distance difference △ speed difference
=45*2÷（80-65）
=90÷15
=6 (hours)
Distance between the two places=
（80+65）*6
=145*6
=870 (km)
What is 15 / 14 times 8 / 3?
=20/7
That's 2 and 6 / 7
Forget to ask: forget even ah
A and B start at the same time from two places of 90 kilometers, and run in opposite directions. The speed ratio of a and B is 7:8. After three fourths of an hour, the two cars meet
What's the speed of each?
The speed ratio of a and B is 7:8. After three fourths of an hour, they meet each other. What's the speed of a and B? Speed sum = 90 ^ (3 / 4) = 120 km / h; speed of a = 120 × 7 ^ (7 + 8) = 56 km / h; speed of B = 56 × 8 ^ 7 = 64 km / h
Speed and speed
=90 △ 3 / 4
=120 km / h
A speed
=120÷（7+8）×7
=56 km / h
B speed
=120-56
=64 km / h
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Speed and speed
=90 △ 3 / 4
=120 km / h
Speed a
=120÷（7+8）×7
=56 km / h
B speed
=120-56
=64 km / h
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Suppose the speed of car a is 7x, then the speed of car B is 8x
（7x+8x）×3/4=90
15x=120
X=8
So the speed of car a is 56 km / h, and that of car B is 64 km / h
Some root of the quadratic equation of one variable X-2 X-5 / 4 is also the root of X-2 + X + 9 / 4, so we can find K
According to the root formula, the value of K can be calculated, and then the two roots of the first equation can be calculated and brought into the second equation respectively
From x ^ 2-2x-5 / 4 = (X-5 / 2) (x + 1 / 2) = 0, the root of the equation is X1 = - 1 / 2, X2 = 5 / 2
(1) If X1 = - 1 / 2 satisfies x ^ 2 - (K + 2) x + 9 / 4 = 0,
Substituting 1 / 4 + (K + 2) / 2 + 9 / 4 = 0,
The solution is k = - 7;
(2) If x = 5 / 2 satisfies the equation x ^ 2 - (K + 2) x + 9 / 4 = 0,
Substituting 25 / 4-5 (K + 2) / 2 + 9 / 4 = 0,
The solution is k = 7 / 5;
In conclusion, k = - 7 or K = 7 / 5